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riddles >> easy >> x^2+x+1
(Message started by: codpro880 on May 7th, 2009, 12:12pm)

Title: x^2+x+1
Post by codpro880 on May 7th, 2009, 12:12pm
If x^2+x+1=0, what is the value of (x^3+1/x^3)^3?

Title: Re: x^2+x+1
Post by pex on May 7th, 2009, 12:49pm

on 05/07/09 at 12:12:28, codpro880 wrote:
If x^2+x+1=0, what is the value of (x^3+1/x^3)^3?

It's [hide]. . . eight . .[/hide] because [hide](x-1)(x2+x+1)=x3-1, so we have x3=1.[/hide]

Title: Re: x^2+x+1
Post by codpro880 on May 10th, 2009, 5:42pm
yep, that was a much more clever solution than what I did. I was dealing with imaginaries...silly me.



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