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Topic: Addition of two Nos. (Read 1200 times) |
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aki_scorpion
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Addition of two Nos.
« on: Jul 12th, 2007, 3:49am » |
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Hi
Addition of two nos. might sound easy .. but is it still so easy if you are not allowed to use ANY operator.
No operators like +,-,*,/,bitwise or logical or any mathematical fn.
Hint : Think along the lines of coding 
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towr
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Re: Addition of two Nos.
« Reply #1 on: Jul 12th, 2007, 4:44am » |
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Every program must constain some operators, otherwise it can't operate. So "any" seems to be overstating the requirements; anything outlawed besides arithmetical, logical or bitwise operators?
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aki_scorpion
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Re: Addition of two Nos.
« Reply #2 on: Jul 12th, 2007, 9:32am » |
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As i mentioned earlier .. no mathematical fn. , arithmetic operators, logical operators, bitwise shold be used. Else u can use any other contraints of programming ...
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SMQ
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Re: Addition of two Nos.
« Reply #3 on: Jul 12th, 2007, 12:09pm » |
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Here's a dirty trick in C: int sum(int a, int b) { return (int)( (((char*)(a))[b])); }
--SMQ
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SMQ
wu::riddles Moderator
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Re: Addition of two Nos.
« Reply #4 on: Jul 12th, 2007, 2:06pm » |
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Without ANY operators:
unsigned int sum(unsigned char a, unsigned char b) {
switch (a) {
case 0:
switch(b) {
case 0: return 0;
}
break;
case 1:
switch(b) {
case 0: return 1;
case 1: return 2;
}
break;
case 2:
switch(a) {
case 0: return 2;
case 1: return 3;
case 2: return 4;
}
break;
[...]
case 255:
switch(b) {
case 0: return 255;
case 1: return 256;
[...]
case 255: return 510;
}
}
return sum(b, a);
}
--SMQ
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Grimbal
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Re: Addition of two Nos.
« Reply #5 on: Jul 12th, 2007, 3:34pm » |
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void printsum(String x, String y)
{
System.out.print(x);
System.out.println(y);
}
numbers are represented in simplified roman notation.
1 = I
2 = II
...
10 = IIIIIIIII
etc.
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aki_scorpion
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Re: Addition of two Nos.
« Reply #6 on: Jul 12th, 2007, 7:24pm » |
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The c trick was awesome SMQ .. tough there is one more such C trick
Here it is
printf("%d",printf("%*s%*s",a" ",b," "));
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towr
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Re: Addition of two Nos.
« Reply #7 on: Jul 13th, 2007, 12:46am » |
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something like
return string('1',a).append('1',b).size()
would also work (return the length of a string of a 1's concatenated by a string of b 1's).
Of course behind the scenes a lot of arithmetic is done.
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| « Last Edit: Jul 13th, 2007, 12:47am by towr » |
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softhacker
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Re: Addition of two Nos.
« Reply #8 on: Sep 6th, 2007, 2:50am » |
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on Jul 12th, 2007, 7:24pm, aki_scorpion wrote:The c trick was awesome SMQ .. tough there is one more such C trick
Here it is
printf("%d",printf("%*s%*s",a" ",b," "));
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hi aki,
1) a=0 and b=20
2) a=-10 and b=20
try above test cases.
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