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Topic: Nights of the round table (Read 830 times) |
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BNC
Uberpuzzler
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Nights of the round table
« on: Feb 3rd, 2003, 9:00am » |
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Around the round table are seated 18 people. Some of them are nights, and some are crooks. The nights always tell the truth (unless they are mistaken) and the crooks always lie. Each of the 18 people claims to be seated between a night and a crook. 1. (easier): If none of the nights are wrong, how many nights are at the table? 2. (a little harder): If two of the nights are wrong, how many nights are at the table?
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How about supercalifragilisticexpialidociouspuzzler [Towr, 2007]
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Phil
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Re: Nights of the round table
« Reply #1 on: Feb 3rd, 2003, 9:55am » |
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Both seem simple. I was going to suggest making it a little tougher still by having each person say, "Among the four people closest to me, 2 are nights and 2 are crooks." But, strangely, both seating charts can stay the same.
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Icarus
wu::riddles Moderator Uberpuzzler
Boldly going where even angels fear to tread.
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Re: Nights of the round table
« Reply #2 on: Feb 3rd, 2003, 6:45pm » |
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There are 2 different numbers of Knights that solve question 1. Question 2 precludes the 2nd possibility, however, so its number of Knights is unique.
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"Pi goes on and on and on ... And e is just as cursed. I wonder: Which is larger When their digits are reversed? " - Anonymous
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BNC
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Re: Nights of the round table
« Reply #3 on: Feb 3rd, 2003, 11:42pm » |
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on Feb 3rd, 2003, 6:45pm, Icarus wrote:There are 2 different numbers of Knights that solve question 1. Question 2 precludes the 2nd possibility, however, so its number of Knights is unique. |
| If I understand your "2nd" possibility, let me state that I thought "some" means "more than 0". Is it wrong?
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How about supercalifragilisticexpialidociouspuzzler [Towr, 2007]
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Icarus
wu::riddles Moderator Uberpuzzler
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Re: Nights of the round table
« Reply #4 on: Feb 4th, 2003, 4:21pm » |
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Usually yes, but sometimes "some" is used to simply indicate the possibility. But I guess that usage is really bad grammar, so I will take it back and agree that 0 knights and 18 crooks is not a valid solution. Sorry about that.
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« Last Edit: Feb 4th, 2003, 4:21pm by Icarus » |
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"Pi goes on and on and on ... And e is just as cursed. I wonder: Which is larger When their digits are reversed? " - Anonymous
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