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Topic: Number sequence (Read 712 times) |
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Thomson
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What is the missing value in the following sequence? 2616, 3, 11, 10850, _____, 25, 2038
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ThudnBlunder
wu::riddles Moderator Uberpuzzler
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Re: Number sequence
« Reply #1 on: Jan 13th, 2005, 10:27pm » |
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Is it Easy?
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THE MEEK SHALL INHERIT THE EARTH.....................................................................er, if that's all right with the rest of you.
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Thomson
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Easy-ish. But it's always like that when you have the answer. -_- I'm not sure, maybe it could be medium or hard.
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puzzlecracker
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Re: Number sequence
« Reply #3 on: Jan 14th, 2005, 6:42pm » |
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this problem doesnt have an answer... he just made it up. be serious please.
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ThudnBlunder
wu::riddles Moderator Uberpuzzler
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Re: Number sequence
« Reply #4 on: Jan 14th, 2005, 9:25pm » |
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on Jan 14th, 2005, 6:42pm, puzzlecracker wrote:this problem doesnt have an answer... he just made it up. |
| So we can just make up an appropriate polynomial to fit the data and find the missing 'value'.
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puzzlecracker
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Re: Number sequence
« Reply #5 on: Jan 14th, 2005, 9:49pm » |
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can you really do that? although the probability is definitely on your side, for he seem not to use primarily prime numbers.. but that interesting
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TenaliRaman
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I am no special. I am only passionately curious.
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Re: Number sequence
« Reply #6 on: Jan 15th, 2005, 1:12am » |
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on Jan 14th, 2005, 9:49pm, puzzlecracker wrote:can you really do that? although the probability is definitely on your side, for he seem not to use primarily prime numbers.. but that interesting |
| Yes definitely. Simply construct the difference table to find the missing value. For finding the polynomial, one can use the Newton's Interpolation Formula.
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rmsgrey
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Re: Number sequence
« Reply #7 on: Jan 15th, 2005, 9:00am » |
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Giving P(xi) for N distinct xi always defines precisely one polynomial P(x) of degree N-1 or less. You get N equations in N unknowns (the coeffecients of the polynomial), and requiring the xi to be distinct guarantees non-degeneracy.
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