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Topic: More Chickens and Eggs (Read 510 times) |
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ThudnBlunder
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More Chickens and Eggs
« on: Aug 7th, 2007, 4:21pm » |
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If a chicken and a half lay an egg and a half in a day and a half, what is the smallest integer number of chickens you need to ensure that an integer number of dozens will be laid in a week?
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Grimbal
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Re: More Chickens and Eggs
« Reply #1 on: Aug 8th, 2007, 3:12am » |
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Hm... can you combine partial eggs from 2 chicken at the end of the week? If a chicken lays 1 egg in 2 days, do 2 chicken lay 7 eggs every week, or 6 eggs the first week (with 2 eggs in process) and 8 the next week?
If the rate is an average (or by carefully starting the biological clock of the chicken with slight offsets), I get:
3/2 chicks lay 3/2 eggs in 3/2 days.
1 chick lays 1 egg in 3/2 days.
1 chick lays 2 eggs in 3 days.
What about a week?
1 chick lays 2·7/3 eggs in 3·7/3 = 7 days.
You want a multiple of 12. Cancel denominator 3 and add a factor 6
18 chicks lay 2·7·6 eggs in 7 days.
18 chicks lay 7 dozen eggs in 7 days.
To actually get full dozens every week, let 6 chicken start on Monday morning, 6 other on Monday afternoon and the last 6 on Tuesday morning. The first team will complete the job on Tuesday afternoon and restart a new cycle. This way, you get 6 eggs every morning and 6 every afternoon. You get exactly 1 dozen every day. Except for the bootstrap period.
This does not take care of week-ends, and holidays (like Christmas and ... Easter).
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| « Last Edit: Aug 8th, 2007, 3:13am by Grimbal » |
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