wu :: forums
« wu :: forums - King Arthur »

Welcome, Guest. Please Login or Register.
May 17th, 2024, 7:24am

RIDDLES SITE WRITE MATH! Home Home Help Help Search Search Members Members Login Login Register Register
   wu :: forums
   riddles
   easy
(Moderators: towr, Grimbal, william wu, ThudnBlunder, Eigenray, Icarus, SMQ)
   King Arthur
« Previous topic | Next topic »
Pages: 1  Reply Reply Notify of replies Notify of replies Send Topic Send Topic Print Print
   Author  Topic: King Arthur  (Read 708 times)
FiBsTeR
Senior Riddler
****





   
WWW

Gender: male
Posts: 581
King Arthur  
« on: Sep 5th, 2007, 6:43pm »
Quote Quote Modify Modify

Sorry if my English isn't gangster-ized...
 
Anyway, this was a warm-up problem I had in my discrete math class today:
 
King Arthur and his twelve knights are to be seated around the Round Table, but they lost the seating arrangement chart. Two seating arrangements are the same iff each person is sitting next to the same two people in both arrangements.
 
a) How many different seating arrangements are there?
 
b) If King Arthur has a special seat to himself, how many different seating arrangements are there?
« Last Edit: Sep 5th, 2007, 6:56pm by FiBsTeR » IP Logged
Sameer
Uberpuzzler
*****



Pie = pi * e

   


Gender: male
Posts: 1261
Re: King Arthur  
« Reply #1 on: Sep 5th, 2007, 7:23pm »
Quote Quote Modify Modify

1) Its a free circular permutation (n-1)!/2. In this case 12!/2
 
My permutation is little weak
 
2) I think if we fixed 1 seat, so it will be 11!/2. Not sure about it though!!
« Last Edit: Sep 5th, 2007, 7:25pm by Sameer » IP Logged

"Obvious" is the most dangerous word in mathematics.
--Bell, Eric Temple

Proof is an idol before which the mathematician tortures himself.
Sir Arthur Eddington, quoted in Bridges to Infinity
SMQ
wu::riddles Moderator
Uberpuzzler
*****






   


Gender: male
Posts: 2084
Re: King Arthur  
« Reply #2 on: Sep 6th, 2007, 8:16am »
Quote Quote Modify Modify

Are mirrored arrangements considered the same?  Each person is sitting next to the same people, but on opposite sides.
 
If not: 1) total permutations of seats divided by number of seats (because rotations around the table are the same) = 13!/13 = 12! 2) total number of permutations of knight's seats (rotations are no longer the same) = 12!.  If mirrored arrangements are the same, divide each of the above by two to account for the symmetry. In either case there's no difference whether or not King Arthur's seat is fixed!
 
--SMQ
IP Logged

--SMQ

rmsgrey
Uberpuzzler
*****





134688278 134688278   rmsgrey   rmsgrey


Gender: male
Posts: 2873
Re: King Arthur  
« Reply #3 on: Sep 6th, 2007, 9:37am »
Quote Quote Modify Modify

on Sep 6th, 2007, 8:16am, SMQ wrote:
In either case there's no difference whether or not King Arthur's seat is fixed!

Which is unsurprising if you think about it - when Arthur's seat isn't fixed, you can always rotate the table so he's in the same place without changing to a different seating arrangement.
IP Logged
FiBsTeR
Senior Riddler
****





   
WWW

Gender: male
Posts: 581
Re: King Arthur  
« Reply #4 on: Sep 6th, 2007, 3:05pm »
Quote Quote Modify Modify

Your second part is correct, SMQ; mirrored arrangements are considered the same by the definition I gave in the problem.
 
If anyone has any problems seeing why the answer does not change when "restricting" the King's seat, notice that you can think of the second question (b) as lining up the knights after the King's seat; the problem thereby loses its "circular" properties.
IP Logged
Pages: 1  Reply Reply Notify of replies Notify of replies Send Topic Send Topic Print Print

« Previous topic | Next topic »

Powered by YaBB 1 Gold - SP 1.4!
Forum software copyright © 2000-2004 Yet another Bulletin Board