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Topic: A fun and interesting IQ question (Read 21210 times) |
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iono
Senior Riddler
dehydrated water....
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Re: A fun and interesting IQ question
« Reply #26 on: Apr 25th, 2008, 7:47pm » |
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All this complicated math is hurting my head.
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So, if I help you, I'll get kicked for ksing, but if I don't, then I'll get kick for not helping...
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FiBsTeR
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Re: A fun and interesting IQ question
« Reply #27 on: Apr 26th, 2008, 7:39am » |
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This is only my very humble opinion, but I usually don't like these problems because there can be so many reasonable interpretations of the sequence that can lead to correct answers, especially in this situation when the sequence is nowhere close to trivial (I don't think).
But if this was the intended answer, then, pardon me, but this would have to be the most unsatisfying solution I've ever seen (not that I've seen too many, though). I don't see any reason why this sequence favors the "solution" posted in the link above any other, except for the fact that it yields the "intended answer", which shouldn't be a reason for a solution to be reasonable (I hope).
If anything, the other solution given in the link (in which the third subtraction is modeled by a quadratic), yields a "wrong" answer, but makes much more sense than the other's "reference to special functions" and what-not.
And when the author of the first solution addressed the second solution, he wrote:
Quote:
Another fine example of extrinsic, finite term fitting sample sufficiency, but unfortunately exhibiting no polymorphic complexity measure beyond the mundane quadratic formula.
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Interpretation: Your answer is too simple, and therefore cannot possibly be correct, especially since it uses the "mundane quadratic formula" (which I don't think it even uses...). My answer must be correct because it is long and "exhibits a polymorphic complexity measure".
Great puzzle.
EDIT:
Actually, the first solution gives an answer of "224" rather than "223" for the next term in the sequence, which does not yield the correct answer to the original problem, so it is actually no more acceptable than any other solution. 
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| « Last Edit: Apr 26th, 2008, 7:48am by FiBsTeR » |
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Sir Col
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impudens simia et macrologus profundus fabulae
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Re: A fun and interesting IQ question
« Reply #28 on: Apr 26th, 2008, 7:58am » |
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I couldn't figure out if Moiety Noire (the author of that "explanation") was testing the story of the "Emperor's New Clothes" or he actually thinks what he is saying makes sense. But whichever way, iono, your hurting head is testimony to the fact that you're not taken in by his drivel.
It is quite possible to find a degree 5 polynomial to fit the given terms:
f(x) = (240 + 1284x - 520x2 + 215x3 - 20x4 + x5)/120
And indeed this generates f(1) = 10, f(2) = 18, f(3) = 32, f(4) = 56), f(5) = 93, and f(6) = 146 as expected, but it gives the next term, f(7) = 219.
I am convinced that the original sequence either contains an erroneous term or it is simply non-determinable based on the information given.
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mathschallenge.net / projecteuler.net
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Grimbal
wu::riddles Moderator
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Re: A fun and interesting IQ question
« Reply #29 on: Apr 26th, 2008, 3:20pm » |
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It could be it is something less mathematical, like adding to each number the number of letters when the number is spelled out, or one column in Mendeleev's periodic table.
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Sir Col
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impudens simia et macrologus profundus fabulae
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Re: A fun and interesting IQ question
« Reply #30 on: Apr 26th, 2008, 4:36pm » |
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Or it could even be the numbers of the last seven buses he saw listed in numerical order!? 
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mathschallenge.net / projecteuler.net
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Simple.paulian
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Re: A fun and interesting IQ question
« Reply #31 on: Dec 13th, 2013, 4:10am » |
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I THEREFORE CONCLUDE THAT...
if ONE * THREE * FIVE = 225 --- then NINE * SEVEN + TWELVE = X --- 225 + X = Y --- 10,18,32,56,93,146,? ---? + Y = Z --- Solve for Z
F1 x f2 x f3 = 225
(1x1) (3x3) (5x) = 225
(1) (9) (25) = 225
225
(9x9) (7x7 )+ (12x12) = x
(81) (49) + 144 = x
3964 + 144 = x
x = 4113
225 + 4113 = y
y = 4338
10,18,32,56,93,146,? + y = z solve for z
(N-#) 2
(18-2) x 2 = 16 x 2 = 32
(32-2) x 2 = 30 x 2 = 60
(60-2) x 2 = 58 x 2 = 116
(116-2) x 2 = 114 x 2 = 228
228 + 4338 = z
z = 4566
4566 (e.4561) (my answer is wrong ..)
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10,18,32,56,93,146,? + y = z solve for z?
then again this Next line analysis.
He/She ask If One* Three* Five* is Equal to 225. Solve for Z?
IF=225 then Z=?
1018325693146? + y = z solve for z
i therefore conclude that. A question mark is what we want to find in order to solve for Z.
(then NINE * SEVEN + TWELVE = X)
x = 9712
135 + 9712 = x
x = 9577
225 + x = y
225 + 9577 = y
y = 9802
? + y = z
? + 9802 = z
(?) = (y) - (x) = z
9802 - 9577 = z
z = 225
If One Three Five is EQUAL to 225 there for the Z is also EQUAL to 225
Y and X is still a letter. A letter plus a number is neither a letter nor a number.
Therefore, Z = undefined.
PROBLEM IS SOVLE <3
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drakula941
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Re: A fun and interesting IQ question
« Reply #32 on: Dec 24th, 2013, 12:31pm » |
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i solved it... by the following method...there might be other as well
ONE*THREE*FIVE=1^2*3^2*5^2=225
NINE*SEVEN+TWELVE=9^2*7^2+12^2=4113=X
225+X=225+4113=4338=Y
10 18 32 56 93 146 ? (difference of all the numbers)
8 14 24 37 53 (difference of these)
6 10 13 16
now ?+Y=Z = Z-Y=?
we have been given 5 values of Z
i used Z-Y for all 5 to get 5 values for ?
out of which 4561-4338=223
if u assume ?=223 and check the difference after 146
it goes like
93 146 223
53 77
24
so it goes 6,10,13,16,24
if u solve Z-Y for all 5 Z and assume Z[i] = ?
you'll notice why 223 = ?
(I AM NOT VERY GOOD AT EXPLAINING STUFF NON-vERBALLY....SORRY)
I FOUND IT VERY VAGUE.... THOUGH I GOT IT RIGHT IN SUBMISSION...BUT UNSATISFIED SOLVING IT.
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| « Last Edit: Dec 24th, 2013, 12:42pm by drakula941 » |
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pengertianbisnis
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Re: A fun and interesting IQ question
« Reply #33 on: May 14th, 2014, 3:42pm » |
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 funny
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UgoLocal02
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Re: A fun and interesting IQ question
« Reply #34 on: Jun 11th, 2014, 11:28pm » |
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I think its capital alphabet's which are confusing us.
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