Author 
Topic: Connect the 6 dots together, is this impossible? (Read 7464 times) 

Etard94
Newbie
Posts: 1


Connect the 6 dots together, is this impossible?
« on: Nov 1^{st}, 2008, 11:38pm » 
Quote Modify

So there is this puzzle, a puzzle which everybody on every site which has this puzzle has claimed to be impossible, but according to my maths teacher is not. Please, I'm like dying for the solution, like literally! And if you can't find the solution, recommend a forum which i can post this puzzle on and get some good responses. And apparently it's a maths problem, so maybe you could maths to solve it, i have no idea ;S . . . . . . Okay, well you have to make each dot connect to the other 5 dots. So like, if you start with the top left dot and connect it to the other 5, do the same to every other dot. So you'll end up with a lot of lines, and they can also curve around the dots, they don't have to go straight. But the thing is, you can't cross the lines, so they can't touch. IS THIS REALLY IMPOSSIBLE!?


IP Logged 



Eigenray
wu::riddles Moderator Uberpuzzler
Gender:
Posts: 1948


Re: Connect the 6 dots together, is this impossibl
« Reply #1 on: Nov 1^{st}, 2008, 11:46pm » 
Quote Modify

It's [edit: not] known as the utilities problem, and it is in fact impossible. There is a nice proof here.

« Last Edit: Nov 2^{nd}, 2008, 11:47am by Eigenray » 
IP Logged 



towr
wu::riddles Moderator Uberpuzzler
Some people are average, some are just mean.
Gender:
Posts: 13097


Re: Connect the 6 dots together, is this impossibl ut.png
« Reply #2 on: Nov 2^{nd}, 2008, 7:48am » 
Quote Modify

You can do the utility problem on a torus (donut). But in the plane (or equivalently on the surface of a sphere) it is impossible (as explained in Eigenray's link). If each dot has to be connected to all five other dots, then it's not quite the same problem, but even more difficult. However, it can still be solved on the surface of some object* (as long as it has enough holes in the right places), just not on the plane. [edit]* Actually, it seems this one can also still be done on a torus.[/edit] [edit2]See attachment, lineends with the same color are connected over the torus/donut (i.e. top and bottom, and left and right wrap together) [/edit2]

« Last Edit: Nov 2^{nd}, 2008, 8:23am by towr » 
IP Logged 
Wikipedia, Google, Mathworld, Integer sequence DB



Eigenray
wu::riddles Moderator Uberpuzzler
Gender:
Posts: 1948


Re: Connect the 6 dots together, is this impossibl
« Reply #3 on: Nov 2^{nd}, 2008, 11:46am » 
Quote Modify

Whoops, you're right. I saw 2 rows of 3 dots and my mind jumped straight to K_{3,3}. Even if there were only 5 dots, it would still be impossible (in the plane). The interesting thing is that the converse holds as well: a graph can be embedded in the plane if and only if it doesn't contain either the utilities graph (K_{3,3}) or the complete graph on 5 vertices (K_{5}) as a minor (that is, by removing vertices, edges, or contracting edges). Edit: There are five dots! How many do you see now?

« Last Edit: Nov 2^{nd}, 2008, 1:46pm by Eigenray » 
IP Logged 



SMQ
wu::riddles Moderator Uberpuzzler
Gender:
Posts: 2064


Re: Connect the 6 dots together, is this impossibl
« Reply #4 on: Nov 2^{nd}, 2008, 1:03pm » 
Quote Modify

on Nov 2^{nd}, 2008, 11:46am, Eigenray wrote:Even if there were only 4 dots, it would still be impossible (in the plane). 
 Eh? SMQ


IP Logged 
SMQ



Hippo
Uberpuzzler
Gender:
Posts: 899


Re: Connect the 6 dots together, is this impossibl
« Reply #5 on: Nov 2^{nd}, 2008, 1:15pm » 
Quote Modify

on Nov 2^{nd}, 2008, 11:46am, Eigenray wrote:Whoops, you're right. I saw 2 rows of 3 dots and my mind jumped straight to K_{3,3}. Even if there were only 4 dots, it would still be impossible (in the plane). The interesting thing is that the converse holds as well: a graph can be embedded in the plane if and only if it doesn't contain either the utilities graph (K_{3,3}) or the complete graph on 4 vertices (K_{4}) as a minor (that is, by removing vertices, edges, or contracting edges). 
 Wow, weeker side of our algebraic hero? Kuratowski theorem talks about divisions of K_{3,3} or K_{5}. And tetrahedron can be projected on sphere easily . Sorry for magnifying that, but until now, I felt everyone expect you Eigenray can be cought as beeing mistaken occasionaly so please take it more like a compliment

« Last Edit: Nov 2^{nd}, 2008, 1:28pm by Hippo » 
IP Logged 



Eigenray
wu::riddles Moderator Uberpuzzler
Gender:
Posts: 1948


Re: Connect the 6 dots together, is this impossibl
« Reply #6 on: Nov 2^{nd}, 2008, 1:43pm » 
Quote Modify

on Nov 2^{nd}, 2008, 1:03pm, SMQ wrote: Strange... I see five. Are you quite sure? Well, looks like I've embarrassed myself enough for one thread. Cheerio!

« Last Edit: Nov 2^{nd}, 2008, 1:52pm by Eigenray » 
IP Logged 



rmsgrey
Uberpuzzler
Gender:
Posts: 2633


Re: Connect the 6 dots together, is this impossibl
« Reply #7 on: Nov 2^{nd}, 2008, 2:00pm » 
Quote Modify

If memory serves, K_{7} can also be done on a torus, though not K_{8}


IP Logged 



Grimbal
wu::riddles Moderator Uberpuzzler
Gender:
Posts: 7009


Re: Connect the 6 dots together, is this impossibl connect7.gif
« Reply #8 on: Dec 6^{th}, 2008, 12:57pm » 
Quote Modify

It does.


IP Logged 



towr
wu::riddles Moderator Uberpuzzler
Some people are average, some are just mean.
Gender:
Posts: 13097


Re: Connect the 6 dots together, is this impossibl
« Reply #9 on: Dec 6^{th}, 2008, 1:29pm » 
Quote Modify

on Dec 6^{th}, 2008, 12:57pm, Grimbal wrote:So obvious once you see it. Wish I thought of it..

« Last Edit: Dec 6^{th}, 2008, 1:30pm by towr » 
IP Logged 
Wikipedia, Google, Mathworld, Integer sequence DB



