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   Author  Topic: Triangles  (Read 864 times)
codpro880
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Triangles   Untitled2.png
« on: Mar 3rd, 2009, 11:34am »
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Equilateral triangle ABC has altitudes BX and AY that intersect at point P. QR, containing point P, is parallel to AC. What fraction of the area of triangle ABC is the triangle PYR?
Explain thoroughly.
 
(I realize I don't have R labeled  Undecided)
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towr
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Re: Triangles  
« Reply #1 on: Mar 3rd, 2009, 12:45pm »
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1/4th
Because P is the center of the equilateral triangle, and so QR is half of AC and QR=QX=XR, which divide the triangle in 4 equal pieces.
« Last Edit: Mar 3rd, 2009, 12:59pm by towr » IP Logged

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Re: Triangles  
« Reply #2 on: Mar 3rd, 2009, 12:53pm »
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on Mar 3rd, 2009, 12:45pm, towr wrote:
1/4th [...] QR is half of AC

Come again?! Wink
 
P is indeed the center of the equilateral triangle, but QR = (2/3)AC, so PR = AC/3.  Moreover, since angle PYR is right, triangle PYR is 30-60-90 with hypotenuse AC/3, and thus half of an equilateral triangle with side AC/3.  Such a triangle would have area 1/9 ABC, so triangle PYR has 1/18 the area of ABC.

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Re: Triangles  
« Reply #3 on: Mar 3rd, 2009, 12:59pm »
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on Mar 3rd, 2009, 12:53pm, SMQ wrote:

Come again?! Wink
Yeah, sorry. I shouldn't be answering puzzles during the opening credits of anime..
[edit]Let alone answering something that isn't even the question[/edit]
 
« Last Edit: Mar 3rd, 2009, 1:01pm by towr » IP Logged

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codpro880
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Re: Triangles  
« Reply #4 on: Mar 3rd, 2009, 5:56pm »
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Yes SMQ.
hahaha towr.
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Re: Triangles   triangle18.GIF
« Reply #5 on: Mar 4th, 2009, 5:41am »
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I count 18.
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