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Title: Prime triplet Post by NickH on Apr 15th, 2003, 2:25pm Show that, if 0 < p and p2 + 2 are primes, then p3 + 2 is also prime. |
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Title: Re: Prime triplet Post by SWF on Apr 16th, 2003, 7:33pm This seems like sort of a trick question. My solution (hidden): [hide]The only p with p2+2 also prime is p=3, and for that p3+2=29, prime, so the statement is true. For all other primes, p, p2+2 is a multiple of 3. Obvious, for p=2, and the rest of the primes are either a multiple of 6 plus 1 or a multiple of 6 plus 5. Plug 6*n+1 or 6*n+5 into p2+2, and you will see it is a multiple of 3.[/hide] |
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Title: Re: Prime triplet Post by NickH on Apr 16th, 2003, 8:21pm Spot on! So, in fact, p4 + 2 is also prime! |
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Title: Re: Prime triplet Post by LZJ on Apr 17th, 2003, 1:50am As for proof as to why 3 is the only value of p possible, p2 (mod 3) = 1 for all odd positive integers that are not multiples of 3, so all other odd primes can be ruled out. |
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