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        riddles >> easy >> What a Meshhh!
        
(Message started by: rloginunix on May 7th, 2015, 7:31pm)
Title: What a Meshhh!
Post by rloginunix on May 7th, 2015, 7:31pm
What a Meshhh!

The number of teeth on each gear is marked right next to it:

http://www.ocf.berkeley.edu/~wwu/YaBBAttachments/rlu_wam.png

If the gear G1 makes one full revolution clockwise then how many revolutions will the gear G2 make?
Title: Re: What a Meshhh!
Post by SMQ on May 8th, 2015, 5:25am
My first thought was that since all the gears on are on separate axles [hide]the intervening ratios don't matter; 21/7 = 3/1[/hide] and so G2 will make [hide]three[/hide] revoloutions for every one of G1.

Then I noticed [hide]there are an odd number of gears in[/hide] the loop containing G2 and so [hide]it is frozen and none of the gears can turn at all[/hide]!

--SMQ
Title: Re: What a Meshhh!
Post by rloginunix on May 8th, 2015, 7:43am

on 05/08/15 at 05:25:48, SMQ wrote:
Then I noticed [hide]there are an odd number of gears in[/hide] the loop containing G2 and so [hide]it is frozen and none of the gears can turn at all[/hide]!

--SMQ


Turns out - you are absolutely correct on this one. Well done.


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