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   Willing to pay more => higher chance it is free
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   Author  Topic: Willing to pay more => higher chance it is free  (Read 1083 times)
amichail
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Willing to pay more => higher chance it is free  
« on: Apr 20th, 2009, 5:03pm »
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Instead of charging $X, why not charge $2X with prob 1/2 and $0 with prob 1/2?
 
More generally, you could let them specify the pay probability p or price $Y >= $X. Given p, have them pay $X/p. Given $Y, make them pay with probability $X/$Y.
 
http://news.ycombinator.com/item?id=569940
 
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towr
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Re: Willing to pay more => higher chance it is  
« Reply #1 on: Apr 21st, 2009, 12:10am »
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on Apr 20th, 2009, 5:03pm, amichail wrote:
Instead of charging $X, why not charge $2X with prob 1/2 and $0 with prob 1/2?
Because most if not all people would go somewhere else to buy.
Suppose you want to buy a house, would you really take the chance of losing twice its value for nothing?
 
Nevermind the problem of trust.
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amichail
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Re: Willing to pay more => higher chance it is  
« Reply #2 on: Apr 21st, 2009, 12:16am »
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on Apr 21st, 2009, 12:10am, towr wrote:

Because most if not all people would go somewhere else to buy.
Suppose you want to buy a house, would you really take the chance of losing twice its value for nothing?
 
Nevermind the problem of trust.

This would be for small purchases.  Moreover, as mentioned above, you could let them pick p or $Y.
 
BTW, you will want to bound the variables, say 0.1 <= p <= 1.0 and price $X <= $Y <= $10X.
« Last Edit: Apr 21st, 2009, 12:19am by amichail » IP Logged

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Re: Willing to pay more => higher chance it is  
« Reply #3 on: Apr 21st, 2009, 5:33am »
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People tend to like it the other way round.
They pay a fixed amount to get a small chance of getting a lot in return.  That's called a lottery.
 
But regarding traffic offenses, it is a bit like that.  You don't pay a fine for each and every traffic offense.  You have some chances of paying $0 and some to pay the full fine.
« Last Edit: Apr 21st, 2009, 5:34am by Grimbal » IP Logged
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