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Topic: Prisms (some math) (Read 7482 times) |
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aero_guy
Senior Riddler
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Re: Prisms (some math)
« Reply #25 on: Sep 17th, 2003, 1:01pm » |
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It looked like people were making some very odd things out of this problem. My analysis gives the same diagram as James's. If alpha=alpha', then the rotational problem already works out, as well as horizontal forces. We just need to show that it works out for vertical forces. Hence we have: Ffcos([alpha])-Fsin([alpha])-mg/2=0 using Ff[smiley=leqq.gif][mu]F so, F[smiley=geqq.gif]mg/2/([mu]cos([alpha])-sin([alpha])) Which is the solution to part 2. For part 1 we notice from the above equation: [mu]cos([alpha])-sin([alpha])>0 or [mu]>tan([alpha]) thus our answer is: [alpha]<atan([mu])
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