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Topic: Variation of Daughter's age problem (Read 2741 times) |
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rmsgrey
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Re: Variation of Daughter's age problem
« Reply #25 on: Dec 1st, 2004, 10:20am » |
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The routine looks good, though I can't be bothered to do a formal correctness proof...
I had wondered a little about the >40 thing, but couldn't convince myself either way...
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SWF
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Re: Variation of Daughter's age problem
« Reply #26 on: Dec 1st, 2004, 6:41pm » |
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I still think "between 2 and 100" means 2 and 100 are not included. I think the answer should therefore be (13,16) instead of (4,13). Although 2 and 100 were included the first time I encountered this problem, one should answer the question posed, not the most similar problem you can find elsewhere.
on Nov 30th, 2004, 9:08pm, Icarus wrote:
No - My argument was that Mr. P's second statement does not help Mr. S sufficiently. For each of the 6 possible values Mr. S had, it still left more than one pair of numbers that satisfied all previous statements. Or so I thought:
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Sorry, I didn't read the details. I thought you had narrowed it down to 4*13 and 8*9.
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