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   THE COEFFICIENT OF x^2
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   Author  Topic: THE COEFFICIENT OF x^2  (Read 1235 times)
pcbouhid
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THE COEFFICIENT OF x^2  
« on: Nov 29th, 2005, 8:30am »
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Find the coefficient of x^2 upon the expansion and collecting of the terms in this expression:
 
((((x - 2)^2 - 2)^2 - 2)^2 - .....- 2)^2
 
------------------------------------
                   (n times)
« Last Edit: Nov 29th, 2005, 8:34am by pcbouhid » IP Logged

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Re: THE COEFFICIENT OF x^2  
« Reply #1 on: Nov 29th, 2005, 9:22am »
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If I had to guess, I'd say (4(2n-1) - 4(n-1)) / 3.
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Re: THE COEFFICIENT OF x^2  
« Reply #2 on: Nov 29th, 2005, 10:13am »
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Well, no reason not to prove your guess:
hidden:
If
a'+b'x+c'x2 = (a-2+bx+cx2)2 (mod x3),
then
a'=(a-2)2, b'=2(a-2)b, and c'=2(a-2)c+b2.
If we start with (a0,b0,c0) = (0,1,0), then (a1,b1,c1) = (4, -4, 1).
Since a1=4, we have an=4 for all n>0, so we can rewrite the recurrence as
b' = 4b,  c' = 4c + b2.
Then clearly bn = -4n, so this becomes
cn+1 = 4cn + 42n,
and c1=1.  This recurrence has the unique solution
cn =  (42n-1-4n-1)/3.

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Re: THE COEFFICIENT OF x^2  
« Reply #3 on: Nov 30th, 2005, 10:31am »
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It seems a good team work with two members: the first make a guess, and the second, prove the guess. Next time, in separate rooms!!!!!!!!!!!!  Grin
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Re: THE COEFFICIENT OF x^2  
« Reply #4 on: Sep 17th, 2007, 6:03pm »
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What if you replaced n with x?
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Re: THE COEFFICIENT OF x^2  
« Reply #5 on: Sep 17th, 2007, 7:14pm »
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on Sep 17th, 2007, 6:03pm, srn347 wrote:
What if you replaced n with x?

What type of number is n?
What type of number is x?
 
 
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Re: THE COEFFICIENT OF x^2  
« Reply #6 on: Sep 17th, 2007, 8:49pm »
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Ask pcbouhid.
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