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   Author  Topic: A Chain of 21 Links  (Read 4942 times)
SAS
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A Chain of 21 Links  
« on: Jul 31st, 2002, 4:03pm »		 Quote Quote Modify Modify Remove Remove
What is the least number of links you can cut in a chain of 21 links to be able to give someone all possible number of links up to 21? What is the least number of links you can cut in a chain of 21 links to be able to give someone all possible number of links up to 21? What is the least number of links you can cut in a chain of 21 links to be able to give someone all possible number of links up to 21? What is the least number of links you can cut in a chain of 21 links to be able to give someone all possible number of links up to 21? What is the least number of links you can cut in a chain of 21 links to be able to give someone all possible number of links up to 21? What is the least number of links you can cut in a chain of 21 links to be able to give someone all possible number of links up to 21? What is the least number of links you can cut in a chain of 21 links to be able to give someone all possible number of links up to 21? What is the least number of links you can cut in a chain of 21 links to be able to give someone all possible number of links up to 21? What is the least number of links you can cut in a chain of 21 links to be able to give someone all possible number of links up to 21? What is the least number of links you can cut in a chain of 21 links to be able to give someone all possible number of links up to 21? What is the least number of links you can cut in a chain of 21 links to be able to give someone all possible number of links up to 21? What is the least number of links you can cut in a chain of 21 links to be able to give someone all possible number of links up to 21? What is the least number of links you can cut in a chain of 21 links to be able to give someone all possible number of links up to 21? What is the least number of links you can cut in a chain of 21 links to be able to give someone all possible number of links up to 21?
« Last Edit: Oct 23rd, 2003, 7:30pm by Icarus » IP Logged
Franklinstein
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Re: New Riddle - Chain 21  
« Reply #1 on: Jul 31st, 2002, 5:41pm »		 Quote Quote Modify Modify Remove Remove
Does this involve giving change back?
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S. Owen
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Solution in 3?  
« Reply #2 on: Jul 31st, 2002, 5:42pm »		 Quote Quote Modify Modify
Cut these links:
 
OooooooOooooOoooooooo
 
to get:
 
o oooooo o oooo o oooooooo
 
Think of two of the single links together as a "2" and you have an 8, 4, 2 and 1 link chain. That gets all values to 15. The 6 then helps you get anything to 21 also.
 
Is there an answer in 2?
« Last Edit: Jul 31st, 2002, 5:43pm by S. Owen » IP Logged
SAS
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Re: New Riddle - Chain 21  
« Reply #3 on: Aug 1st, 2002, 4:29am »		 Quote Quote Modify Modify Remove Remove
Answer to Franklinstein:
Yes, it does involve giving change back.
 
Answer to srowen:
Yes, there is.  Wink
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Eric Yeh
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Re: New Riddle - Chain 21  
« Reply #4 on: Aug 3rd, 2002, 7:39am »		 Quote Quote Modify Modify
This is not a loop, right?  So just cut off two links to leave three pieces of lengths 3, 6, and 10.  
 
It seems to me this is even expandable to 1+1+3+6+12 = 23 link chain, too, no??  What am I missing?
 
Eric
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"It is better to have puzzled and failed than never to have puzzled at all."
SAS
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Re: New Riddle - Chain 21  
« Reply #5 on: Aug 5th, 2002, 12:02pm »		 Quote Quote Modify Modify Remove Remove
No, it is assumed that we don't have a loop. And your answer is right on target. And you're right about 23, too. To better present the solution I would suggest this:
 
000 C 000000 C 000000000000 000 C 000000 C 000000000000 000 C 000000 C 000000000000 000 C 000000 C 000000000000 000 C 000000 C 000000000000 000 C 000000 C 000000000000 000 C 000000 C 000000000000 000 C 000000 C 000000000000 000 C 000000 C 000000000000 000 C 000000 C 000000000000 000 C 000000 C 000000000000 000 C 000000 C 000000000000 000 C 000000 C 000000000000 000 C 000000 C 000000000000

 
The catch in this riddle is that once you cut a link you can seperate and use it as a single element.
 
Thanks for checking everybody!  
 
Cheesy
 
 
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Eric Yeh
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Re: New Riddle - Chain 21  
« Reply #6 on: Aug 5th, 2002, 12:08pm »		 Quote Quote Modify Modify
Yup -- thanks for the riddle, SAS.  Check out the new ones I posted in the hard section.  Smiley
 
Looking forward to hearing more of your problems!!
 
Best,
Eric
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"It is better to have puzzled and failed than never to have puzzled at all."
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