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wu :: forums    riddles    medium (Moderators: william wu, towr, Grimbal, ThudnBlunder, Icarus, Eigenray, SMQ)    sum of distinct cubes « Previous topic | Next topic » Pages: 1  Reply Notify of replies Send Topic Print    Author  Topic: sum of distinct cubes  (Read 768 times) Christine Full Member     Posts: 159 sum of distinct cubes   « on: Aug 14th, 2014, 9:42am » Quote Modify Cubes with a representation as a sum of distinct cubes :   Some end with a 1^3  : 9^3 = 8^3 + 6^3 + 1^3   others don't : 6^3 = 5^3 + 4^3 + 3^3   Is the set of those that don't finite or infinite?   How to prove it?   IP Logged towr wu::riddles Moderator Uberpuzzler Some people are average, some are just mean.     Gender: Posts: 13730 Re: sum of distinct cubes   « Reply #1 on: Aug 14th, 2014, 10:08am » Quote Modify multiply by n^3 if a^3 = b^3 + c^3 + d^3 then (an)^3 = (bn)^3 + (cn)^3 + (dn)^3 IP Logged Wikipedia, Google, Mathworld, Integer sequence DB Pages: 1  Reply Notify of replies Send Topic Print Forum Jump: ----------------------------- riddles -----------------------------  - easy => medium   - hard   - what am i   - what happened   - microsoft   - cs   - putnam exam (pure math)   - suggestions, help, and FAQ   - general problem-solving / chatting / whatever ----------------------------- general -----------------------------  - guestbook   - truth   - complex analysis   - wanted   - psychology   - chinese « Previous topic | Next topic »

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