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Topic: Re: Deal 2 cards, probability of potential RF or p (Read 2195 times) |
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rmsgrey
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Re: Deal 2 cards, probability of potential RF or p
« on: Sep 9th, 2016, 12:47pm » |
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Either I'm misreading the question, or it's a very boring one.
The probability of there being a pair of aces left in the 50 cards remaining is 1, never mind any less specific combination...
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Michael Dagg
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Re: Deal 2 cards, probability of potential RF or p
« Reply #1 on: Sep 9th, 2016, 8:03pm » |
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Proposition.
Let SS be a sample space on which a probablistic question is
asked regarding its partition into two sets by some means.
If the answer to that question is true, then p =1. Conversely, if p =1, the answer is true.
True, False?
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Regards,
Michael Dagg
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