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        riddles >> medium >> MasterMind II soln
        
(Message started by: zeb on Jul 30^th, 2002, 1:08pm)

Title: MasterMind II soln
Post by zeb on Jul 30^th, 2002, 1:08pm

G: Green
R: Red
Y: Yellow
B: Brown
L: Light Blue
D: Dark Blue

black peg: .
White peg: o

reversing the order, my apologies:
1) LDRG o
2) LYGB .o
3) GGYL ..
4) YGLB .o
5) ----? ....

1) tells us one of these is part of the solution but no others.
L has no obvious conflicts
D breaks at 3), since if LDG are all not part of the solution, then 3) can’ t have two black pegs.
R likewise breaks at 3) for the same reason
G has no obvious conflicts.

Assume G is the o from 1), LDR are all out.
2) Either Y, G or B is the .
If Y, then G isn’t in either of the last 2 so GY-- would be true. But that cannot be since it would give at least one white peg for 3) instead of the .. we see.
If G, then --G- is all we know and Y or B is misplaced.
Y can’t be the misplaced one since 3) would then show a white peg. For there to be only black pegs would put Y and G on the same spot, so Y isn’t the one.
If B is misplaced, then 3) would not work since YL are not true for this tree, leaving GG as true and sitting on the only spots where B could be true. B ain't it.
So G is not the one.

Which leaves L. But, to be sure (or if you start with L instead of G)…

Assuming L, 1) tells us DRG are all out.
So 3) then tells us --YL is part of the solution.
B cannot be part of the solution. If it were, then B-YL or –BYL would make 4) show 3 pegs, and 2) would show 3 pegs, which they don’t.
So that leaves only Y and L for the remaining spots.
L can’t be in the first spot because of 1). So, Y must be there.
2) tells us Y is in the 2nd spot too, since L is still the white peg from 1).

YYYL.

Title: Re: MasterMind II soln
Post by Snack on Aug 21^st, 2002, 3:23pm

I got exactly the same thing.

I started by going through all the possibilities created by 3 and then working from there. :-)

YYYL

Title: Re: MasterMind II soln
Post by allie on Nov 14^th, 2002, 9:01am

*Sigh* Nope, I can't see it. If indeed 3 tells us that --YL must be true, then 2 would have 2 "o"'s (since the colors are right but the position isn't). Instead it has ".o". So if you accept that YL are in the final, it's either "L-Y-" (which can't be because of 3) or "-Y-L" (which can't be beacuse of 3). So "YL" can't be part of the final solution because 3 says they would have to be in 3rd and 4th position, and 2 does not have 2 color only marks to support that. *Sigh again* Did I explain that well? Can anyone explain this one to me?