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riddles >> medium >> Dan's Farm
(Message started by: ThudanBlunder on Sep 19th, 2007, 2:33pm)

Title: Dan's Farm
Post by ThudanBlunder on Sep 19th, 2007, 2:33pm
Although The Farm, a rectangular piece of land, has been in Dan's family for a good number of years, he is thinking of selling it, as Britain has just declared war on Hitler.  

ACROSS
1. Area in square yards of The Farm.
5. Age of Molly, Dan's aunt.
6. Number of yards difference between length and width of The Farm.
7. Area of The Farm in quarter-acres times 8 Down.
8. The year Dan's family bought The Farm.
10. Dan's age.
11. Year of Maria's birth.
14. Perimeter in yards of The Farm.
15. Dan's mph walking speed cubed.
16. 15 Across take away 9 Down.

http://www.ocf.berkeley.edu/~wwu/YaBBAttachments/Dan's_Farm.gif

DOWN
1. Five times the value of The Farm in pounds sterling per acre.
2. Age of Dan's mother-in-law squared.
3. Age of Maria, Dan's daughter.
4. Value in pounds sterling of The Farm.
6. Age of Tom, Dan's son, who will be twice Maria's age in 1945.
7. Square of the width of The Farm.
8. The number of minutes it takes Dan to walk 4/3 times round The Farm.
9. 10 Down divided by 10 Across.
10. See 9 Down.
12. One more than the sum of the digits of 10 Down.    
13. The number of years The Farm has been in Dan's family.

(1 mile = 1760 yards; 1 acre = 4840 square yards.)


Title: Re: Dan's Farm
Post by Barukh on Sep 20th, 2007, 4:24am
What happened to the picture? I can't see it!

Title: Re: Dan's Farm
Post by ThudanBlunder on Sep 20th, 2007, 4:42am

on 09/20/07 at 04:24:21, Barukh wrote:
What happened to the picture? I can't see it!

You were getting too close!   :P

I want to put the picture in the middle using [img][/img]. The gif is on the server, so why doesn't it come up when referenced?

Title: Re: Dan's Farm
Post by towr on Sep 20th, 2007, 5:01am

on 09/20/07 at 04:42:52, ThudanBlunder wrote:
You were getting too close!   :P

I want to put the picture in the middle using [img][/img]. The gif is on the server, so why doesn't it come up when referenced?
It is only on the server while it's attached. If you remove it as attachment, it is also removed from the server. If you want it shown in the post, rather than under it, you might try attaching it as txt and linking that as an image.

Title: Re: Dan's Farm
Post by Barukh on Sep 20th, 2007, 5:27am

on 09/20/07 at 04:42:52, ThudanBlunder wrote:
You were getting too close!   :P

No, I am stupid.

Title: Re: Dan's Farm
Post by ThudanBlunder on Sep 20th, 2007, 7:09am

on 09/20/07 at 05:27:13, Barukh wrote:
No, I am stupid.

What happened to your PMed allleged contradictions?  :P

Title: Re: Dan's Farm
Post by Barukh on Sep 20th, 2007, 7:23am

on 09/20/07 at 07:09:15, ThudanBlunder wrote:
What happened to your PMed allleged contradictions?  :P

[hide]I haven't thought a farm could be in possession of a single family for so long[/hide]...

I wonder: how much such a farm costs nowadays in England?

Title: Re: Dan's Farm
Post by ThudanBlunder on Sep 20th, 2007, 7:43am

on 09/20/07 at 07:23:04, Barukh wrote:
I wonder: how much such a farm costs nowadays in England?

Between 1 and 2 million pounds (US$2-4m), I am told.


Title: Re: Dan's Farm
Post by ThudanBlunder on Sep 21st, 2007, 12:08pm
Well, is nobody going to post a solution for this nice puzzle?

Title: Re: Dan's Farm
Post by Sameer on Sep 21st, 2007, 2:05pm

on 09/21/07 at 12:08:36, ThudanBlunder wrote:
Well, is nobody going to post a solution for this nice puzzle?


I will work over weekend on this!!!

Edit: I tried a little and saw myself going round and round!! Any hints would be appreciated!!

Title: Re: Dan's Farm
Post by FiBsTeR on Sep 21st, 2007, 6:29pm

on 09/19/07 at 14:33:38, ThudanBlunder wrote:
9. 10 Down divided by 10 Across.
10. See 9 Down.


Does "See 9 Down" mean that 10 Down is equal to 9 Down? In that case:

(10 Down) = (10 Down) / (10 Across)
(10 Across) = 1
Dan's Age = 1

??? I guess I'm misinterpreting...

EDIT: Ah, maybe you mean that 10 Down can be ascertained only by getting 9 Down first...

Title: Re: Dan's Farm
Post by SWF on Sep 21st, 2007, 8:00pm
Here is a hint: I started with first digit of 11 across must be 1, since this is prior to 1945 (and assumed no leading zeros), then was able to figure out cube of walking speed.

I didn't notice the Hitler clue until only 5 more cells left to fill and can't help but wonder if using that sooner would have made it easier.
[hide]
38720X5
4X91X44
0X2X384
X1110XX
72X1918
9XXX792
27X16X9
[/hide]

Title: Re: Dan's Farm
Post by towr on Sep 22nd, 2007, 3:09am

on 09/21/07 at 12:08:36, ThudanBlunder wrote:
Well, is nobody going to post a solution for this nice puzzle?
Didn't Barukh post one?

Title: Re: Dan's Farm
Post by ThudanBlunder on Sep 22nd, 2007, 12:13pm

on 09/22/07 at 03:09:14, towr wrote:
Didn't Barukh post one?

But I'm a bit weird, I differentiate between answers and solutions.   :P

Title: Re: Dan's Farm
Post by ThudanBlunder on Sep 22nd, 2007, 12:17pm

on 09/21/07 at 18:29:11, FiBsTeR wrote:
EDIT: Ah, maybe you mean that 10 Down can be ascertained only by getting 9 Down first...

It simply means 10 Down depends on 9 Down.

Title: Re: Dan's Farm
Post by Barukh on Oct 3rd, 2007, 2:21am

on 09/22/07 at 12:13:41, ThudanBlunder wrote:
But I'm a bit weird, I differentiate between answers and solutions.   :P

Here's one:

The solution is somewhat simplified by the fact that the problem is put in a certain historical context. For instance, this almost immediately implies 9D = 11.

Proceed with 15A, which can be 27 or 64. If 15A = 64, we must have 8D = 16, but then 14A = 8D * 88 > 1000, which is impossible. Therefore, 15A = 27, 8D = 12, 14A = 8D * 66 = 792. Applying the conditions for 12D, 10A, 10D, I found the only possible case 10A = 72, 10D = 792, 12D = 19. Also, 11A = 191?, 7D = ??976, which has a unique solution 30976 as a perfect square. Thus, the dimensions of the farm are determined (220 x 176), and 1A = 38720, 6A = 44.

Now, from the condition 6D, 3D is determined uniquely to be 21. The rest is straightforward.



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