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Title: Squares: sums and differences Post by Christine on Mar 11th, 2013, 1:23pm My question is: how do you find sums and differences that are both squares? x + y is a square x - y is a square |
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Title: Re: Squares: sums and differences Post by towr on Mar 11th, 2013, 1:44pm (u+v)^2-u^2 = 2uv+v^2 = 2y x = u^2+y So basically we can take any u paired with an even v. |
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Title: Re: Squares: sums and differences Post by pex on Mar 11th, 2013, 1:46pm Or, equivalent but perhaps simpler: take any two squares that are either both even or both odd, say a2 and b2, and let x = (a2 + b2)/2 and y = (a2 - b2)/2. |
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Title: Re: Squares: sums and differences Post by Immanuel_Bonfils on Mar 11th, 2013, 5:01pm No restriction to x and y (unless being real, y guess), so parity doesn't matter, even b>a -> (y <0) would be OK |
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Title: Re: Squares: sums and differences Post by Grimbal on Mar 12th, 2013, 4:00pm It wasn't stated, but usually these problems ask for integer solutions. If you are working with reals, every number >=0 is a square. A simple set of solutions is x=a2 for some a and y=0. It doesn't feel like a proper solution though. On the other side, pex's method gives all integer solutions. |
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Title: Re: Squares: sums and differences Post by Christine on Mar 19th, 2013, 10:34am Thank you all for the feedback. Sorry I did not state that > I was looking for integer solutions, > for producing interesting results (e.g. squares of prime numbers) I'll make sure that next time I'll state clearly my questions. |
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