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Title: quadruple Post by Christine on Sep 15th, 2013, 4:56pm Diophantus quadruple (1/16, 33/16, 17/4, 105/16) the product of any two distinct terms + 1 is a square How can you find other sets of rational quadruple? |
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Title: Re: quadruple Post by SEMfuze on Sep 27th, 2013, 7:20am y 2 = (a1x + n)(a2x + n)(a3x + n)(a4x + n)(a5x + n) |
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Title: Re: quadruple Post by Christine on Sep 27th, 2013, 9:40am on 09/27/13 at 07:20:19, SEMfuze wrote:
It doesn't look right. Maybe I miss something here. Please clarify. |
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Title: Re: quadruple Post by towr on Sep 27th, 2013, 2:35pm I think he meant to copy/paste the formula for a hyperelliptic curve y2 = (a1x + 1)(a2x + 1)(a3x + n)(a4x + 1)(a5x + 1) (n=1 in this case). Equation 2 on page 2 of http://arxiv.org/pdf/math/0002088.pdf, for example (I haven't read it, and not sure how much I'd understand of it if I would). |
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Title: Re: quadruple Post by Christine on Sep 27th, 2013, 5:15pm on 09/27/13 at 14:35:19, towr wrote:
Ouch! Thanks. The stuff on arxiv is tough to understand. The question I posted is more difficult than I anticipated. |
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