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   Author  Topic: Complex Sum  (Read 776 times)
Sameer
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Pie = pi * e

   


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Complex Sum  
« on: Sep 11th, 2007, 11:27pm »
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Going by Complex numbers and summation themes!! Trying to read up for solving these, I found an interesting problem from my Engineering Math book!!
 
 
Find the Sum of the series:
 
sin2x - (1/2)sin(2x)*sin2x + (1/3)sin(3x)*sin3x - (1/4)sin(4x)*sin4x + ...
« Last Edit: Sep 11th, 2007, 11:28pm by Sameer » IP Logged

"Obvious" is the most dangerous word in mathematics.
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Proof is an idol before which the mathematician tortures himself.
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iyerkri
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  iyerkri  


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Re: Complex Sum  
« Reply #1 on: Sep 11th, 2007, 11:53pm »
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After a lot of questionable mathematics, I arrive at :
hidden:

arctan ( (tan x)^2/(1 + tanx + (tan x)^2)).
 
I am not to able to simplify further. I considered a similar series where sin kx is replaced by coskx, added the two, getting a power series in exp(ix)sinx, which evaluates to log(1 + exp(ix)sinx) , whose imaginary part is of interest to us, which is the above expression.
 
obviously I ignore the many branches of log and all.....
« Last Edit: Sep 11th, 2007, 11:54pm by iyerkri » IP Logged
Eigenray
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Re: Complex Sum  
« Reply #2 on: Sep 12th, 2007, 2:31am »
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Different branches of log are not a problem here.  (eix)k = eikx when k is an integer (but not in general!).  And - (-x)k/k = log(1+x), the principal branch, as long as |x|<1, which it is in this case (except when |sin(x)|=1, but this isn't a problem).
« Last Edit: Sep 12th, 2007, 2:54am by Eigenray » IP Logged
Barukh
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Re: Complex Sum  
« Reply #3 on: Sep 15th, 2007, 8:26am »
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Extremely nice approach, iyerkri!  
 
 Cheesy
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iyerkri
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Re: Complex Sum  
« Reply #4 on: Sep 16th, 2007, 1:52pm »
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thanks. By the way, that was probably my first correct post on the forum!
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