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   Author  Topic: Complex roots  (Read 2135 times)
Grimbal
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Re: Complex roots  
« Reply #25 on: Sep 27th, 2007, 12:34am »
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on Sep 26th, 2007, 7:23pm, srn347 wrote:
As already stated, you need to have all the n's answered. x would have to equal n-1.

I guess you mean x-1.
 
Sorry to tell you that, but your understanding of mathematics is a complete mess.
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towr
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Re: Complex roots  
« Reply #26 on: Sep 27th, 2007, 2:08am »
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on Sep 26th, 2007, 7:23pm, srn347 wrote:
As already stated, you need to have all the n's answered. x would have to equal n-1.
Perhaps you misunderstand the question. What is asked for is not a single value for x that works for all n; what is asked for is an expression which given any n, provides values for x that satisfy the equation.
 
on Sep 26th, 2007, 9:39pm, Sameer wrote:
Note to Mods: Can you please delete posts that are irrelevant to this thread? You get my drift!!
If this final attempt at explanation fails, I'll be glad to. So that should be in under a day.
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Re: Complex roots  
« Reply #27 on: Sep 27th, 2007, 4:46pm »
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Oh individual values. Obviously the evens are already solved. Some exponents may have multiple solutions.
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pex
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Re: Complex roots  
« Reply #28 on: Sep 28th, 2007, 12:10am »
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on Sep 27th, 2007, 4:46pm, srn347 wrote:
Oh individual values. Obviously the evens are already solved. Some exponents may have multiple solutions.

srn347 - A complete solution was outlined in the first three replies to this thread. Indeed, there are multiple solutions: n-1 for every n.
« Last Edit: Sep 28th, 2007, 12:11am by pex » IP Logged
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