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   Author  Topic: harmonic  (Read 4622 times)
temporary
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Re: harmonic  
« Reply #50 on: Jan 27th, 2008, 4:09pm »
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Yet sm347 posted only spam, while srn347 at least tried to solve the riddles. For further discussion, http://www.ocf.berkeley.edu/~wwu/cgi-bin/yabb/YaBB.cgi?board=riddles_gen eral;action=display;num=1201066684
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My goal is to find what my goal is, once I find what my goal is, my goal will be complete.
Obob
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Re: harmonic  
« Reply #51 on: Jan 27th, 2008, 5:48pm »
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To be honest, nobody cares if srn347 and sm347 are/were the same person.  Whether you and srn347 are the same person (and I am 99% sure you are) is much more pertinent.
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Eigenray
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Re: harmonic  
« Reply #52 on: Jan 27th, 2008, 7:02pm »
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In any case, temporary and srn347 both certainly tend to sully any thread they touch.
 
Getting back on topic, it was still to be shown that
 
Sr = 1/1 + 1/2 + ... + 1/r - 1/(r+1) - 1/(r+2) - ... - 1/(2r)
   + 1/(2r+1) + ... + 1/(3r) - 1/(3r+1) - ... - 1/(4r)
   + 1/(4r+1) + ....
 = 1/r [ log 2 + 2 tan ]
 ~ log(2r/) + ,
 
where the sum is over = k/2r,  k= r-1, r-3, r-5, ..., k 1.
 
In fact it looks like
 
Sr ~ log(2r/) + + log(2)/r - 0.137078/r2
 
Any takers?
« Last Edit: Jan 27th, 2008, 7:26pm by Eigenray » IP Logged
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Re: harmonic  
« Reply #53 on: Jan 27th, 2008, 7:31pm »
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on Jan 27th, 2008, 5:48pm, Obob wrote:
To be honest, nobody cares if srn347 and sm347 are/were the same person.  Whether you and srn347 are the same person (and I am 99% sure you are) is much more pertinent.

 
Wasn't srn347 ip banned also, or is that just a myth. Also, if what you are saying is true, then
 
1/1 + 1/2 + ... + 1/r - 1/(r+1) - 1/(r+2) - ... - 1/(2r)
   + 1/(2r+1) + ... + 1/(3r) - 1/(3r+1) - ... - 1/(4r)
   + 1/(4r+1) + .... ~ log(2r/) +  + log(2)/r - 0.137078/r2
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My goal is to find what my goal is, once I find what my goal is, my goal will be complete.
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