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        riddles >> putnam exam (pure math) >> Another Sine Product
        
(Message started by: CSter on May 18^th, 2004, 4:24pm)

Title: Another Sine Product
Post by CSter on May 18^th, 2004, 4:24pm

Here is a sine product formula that I've run across:

n = 2^n-1[prod]_k=1^n-1sin(k[pi]/n)

Anyone familiar with it? Can you prove it?

Title: Re: Another Sine Product
Post by Icarus on May 18^th, 2004, 10:18pm

See my post in the other thread.