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Title: Square Root, Floor, and Factorial Post by THUDandBLUNDER on Jan 5th, 2007, 10:00am Express the numbers 4 to 9 as economically as possible using only one '3' and as many square root, floor, and (standard) factorial functions as you require. eg, 1 requires 2 operations as 1 = floor(sqrt(3)) or FS3, for short. 2 requires 3 operations as 2 = floor(sqrt(3!)) or FS(3!), for short. |
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Title: Re: Square Root, Floor, and Factorial Post by SMQ on Jan 5th, 2007, 10:43am Is the "standard" factorial of a non-integer well defined for this problem? If not, I'm seeing: 4. [hide]FSSSSSS((FSSSSSSS(((FSS(3!!))!!))!)[/hide] (23 operations) 5. [hide]FSS(3!!)[/hide] (5 operations) 6. 3! (1 operation) 7. [hide]FSSSSSSSSSSS(3!!!)[/hide] (15 operations) 8. [hide]FSS((FSSSSSSSSSSS(3!!!))!)[/hide] (19 operations) 9. [hide]FSSSS((FSSSSSSSSS((FSSSS((FSSSSSSS((FSS(3!!))!!))!))!))!)[/hide] (38 operations) [edit] expanded references and added 9 from below [/edit] --SMQ |
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Title: Re: Square Root, Floor, and Factorial Post by THUDandBLUNDER on Jan 5th, 2007, 11:21am on 01/05/07 at 10:43:45, SMQ wrote:
Nope. |
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Title: Re: Square Root, Floor, and Factorial Post by SMQ on Jan 5th, 2007, 12:10pm 9. [hide]FSSSS((FSSSSSSSSS((FSSSS((FSSSSSSS((FSS(3!!))!!))!))!))!)[/hide] (38 operations) --SMQ |
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Title: Re: Square Root, Floor, and Factorial Post by ThudanBlunder on Apr 30th, 2007, 12:00pm on 01/05/07 at 12:10:18, SMQ wrote:
Can be done in 36 |
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