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Title: An inequality Post by acarchau on Dec 14th, 2008, 9:48pm Prove/disprove, for x>=0 (1+x)^(1+x) >= 1+x+x^2 |
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Title: Re: An inequality Post by towr on Dec 15th, 2008, 1:38am [hide] take f(x) = (1+x)^(1+x) g(x) = 1+x+x^2 then f(0)=g(0) f'(0)=g'(0) f''(x) >= g''(x) for x>=0 so (since they are continuous) f(x) >= g(x) for x>=0 [/hide] |
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Title: Re: An inequality Post by ThudanBlunder on Dec 15th, 2008, 3:30am [hide]Binomial Theorem[/hide]. |
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