tseitsei

Average Moves: 29.44
Score: 3
Current Mean of 3: 26.67 (22, 26, 32)
Best Mean of 3: 26.67 (22, 26, 32)
Move Count Scramble Solution Comments
22 L2 D' F2 U R' D F' L' R' U B2 F' L U B R B F2 U' B2

F' R L2 U2 B' L' B L U B U2 B' U B2 U2 B' D' B U2 B2 R D

https://www.speedsolving.com/forum/threads/the-fmc-thread.13599/page-185#post-1175521

Explanation behind the link

26 L2 D2 F2 U' D F' R L2 B' R L2 U D2 R' U F L B' R' B'

B' L2 U L2 B L' U D L U L' D' L B L2 F2 L' F' U B2 L F' L' B2 L F

on inverse:
L' U' F L F2 //2x2
L2 B' U' L' U' // 2 squares
And now we see that those squares will form F2L if we use pre moves L' B or B L' so we try both. I found better continuation with L' B.
so on inverse with premoves L' B:
L' [2] U' F L F2 //2x2
L2 B' [1] U' L' U' // 2 squares
L B' L2 U' L' // All but 4 corners

[1] = [L' D L : U'] 4-moves cancel
[2] = [L F' L' : B2] 2-moves cancel

32 F2 B D R L F2 R' B' L2 U R2 L2 F R2 L D2 B' F2 L' U2

L' B' R2 B D' F2 R' F R' D' R F R2 D' B' R2 B2 R' F R B2 R' F2 R' B R F' R F' R' F2 D2

34 U R2 D2 F' R' D' F2 L2 D' B2 L D U2 B2 F U2 D2 F B' L2

U' F R L U F R2 F' L' F R2 F' B2 R2 B' D' B U B' D B R U2 F R2 F' R' F R F' R F2 U2 F'

on inverse:
F U2 F2 //2x2
on normal:
U' F R L U L' [1] B2 /2x2x3+pair
R2 U [2] R U2 //F2L-1+EO
F R2 F' R' F R F' R //L5C (so bad...)

[1]=[L: F R2 F']
[2]=[U': B' D' B]

27 D2 F2 U' R' D2 L' B' U' L2 F R B R' U' B' D2 U' L' U L'

B R B2 R B U2 R U R' B' R' D' B L2 B' R2 B L2 B' R' D R' U2 D2 B2 R' U

on inverse:
U' R B2 D2 //2x2
back to normal
B R // interesting pseudo-square on down back right :)
so now I add premove U2 to fix pseudoness of that square.

So on normal with premoves U2 D2 B2 R' U
B2 R B U2 R // another square
U R' B' //F2L-1+EO+square on last layer
R' D' R D R' // All but 3 corners

skeleton: B R B2 R B U2 R U R' B' R' D' [1] R D R' U2 D2 B2 R' U

[1]=[B L2 B' : R2]

only 1 move cancels. Afterwards I checked IF and it says 2 moves is optimal. So I am an idiot and missed PB...

Still a nice solve for me :)

29 D B2 R D F B2 D U2 L U F2 D U2 B2 R B U' R L' D

D U L' U' B' F D' F' U F D F' B R B2 R' L2 B2 U2 B D' B' U' B R F D F' R2

on inverse with premove D'

R2 F D' F' R' D [1] //2x2 + pair
B' U' B2 //square
L2 R B2 R' //f2l-1 almost ready
B' [2] U' B U L U' //L4C (2 2-cycle)

[1] = [D' : B' U B] 5-moves cancel :)
[2] = [F D' F' : U'] 2-moves cancel

36 D2 F2 R' U2 F L' R' F B2 D2 L F R2 B L2 U' B' R2 B' L'

D2 B D F2 D' B' D F2 B' D U' B F D' F2 L D L F' L' D' R' Dw2 R' U2 R Dw2 R' U2 R' F L2 F' R' F L2

Pre-move F

D' [1] B' D U' B //2x2
F D' F2 L D //square
L F' L' D' // pseudoF2L (kind of...)
R' Dw2 R' U2 R Dw2 R' U2 R2 [2] // pair commutator that leaves 4C

Had less than 10 minutes to do the insertions so they are quite bad probably...

[1]=[D' B D : F2]
[2]=[R : F L2 F']

2-moves cancel

27 L' B U2 F' R D' F' R' U2 D' B U' R2 D2 B R' L2 B' R2 L2

D2 F' L2 F R' D' L D R D' U' B2 U F U' B2 U D F D' F' L2 D U2 L2 F B2

On inverse:
B2 F' L2 U2 //2x2
Switch to normal (premoves: U2 L2 F B2)
D2 F' L2 //pseudo 2x2x3
Fix pseudoness with premove D (premoves D U2 L2 F B2)
F D' L //pseudo F2L-1 + pair
Again we fix pseudoness with premove L2 (so premoves L2 D U2 L2 F B2)
F D F D' F' //solve edges (and 1 corner) leave 3-cycle+1twistedc

skeleton:D2 F' L2 F D' [1] L F D F D' L F' L2 D U2 L2 F B2 (17)

[1]=D R' D' L D R D' [2] L'
[2]=U' B2 U F U' B2 U F'

solution: D2 F' L2 F R' D' L D R D' U' B2 U F U' B2 U (F' L' L F) D F D' F' L2 D U2 L2 F B2 31moves

4 moves cancel so 27 moves :) very good for me

32 R2 U' D2 L R2 B' D2 F2 L2 R' F' B' D' L F U' L' F2 D' B'

B2 R2 L F R2 U2 B R' B' U L' B R2 B' L B R2 U2 B R B2 R' B' D L' D' R D L D' R2 U

B2 R2 L F //2x2 4/4
R2 U2 //square 2/6
B R' // pseudo2x2x3 + a pair on UB-UBR 2/8
B' U B U2 // pseudo F2L-1 4/12
Now I used pre-moves R' U to correct pseudoness
B R B2 R' B' //leave 5 corners 5/17
R' U //undo premoves 2/19

Skeleton: B2 R2 L F R2 U2 B R' B' U (1) B R2 U2 B R B2 R' B' (2) R' U (19moves)

(1)=[L':BR2B'] 2-moves cancel
(2)=[DL'D':R] 1-move cancels


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