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5. (Free discussion problem, no points taken). Let $f: [0,1] \to \R$ be a real bounded function. Assume $f(x) \geq 0$ and $f$ is Riemann integrable. Here is a candidate that measures the area under the graph of $f$: | 5. (Free discussion problem, no points taken). Let $f: [0,1] \to \R$ be a real bounded function. Assume $f(x) \geq 0$ and $f$ is Riemann integrable. Here is a candidate that measures the area under the graph of $f$: | ||
- | * For each positive integer $n$, let $N(n)$ be the number of points $(x,y) \in \R^2$, such that $x, y \in \Z / 2^n$, and $x \in [0,1], 0 \leq y \leq f(x)$. Namely, we count how many points in the lattice | + | * For each positive integer $n$, let $N(n)$ be the number of points $(x,y) \in \R^2$, such that $x, y \in \Z / 2^n$, and $x \in [0,1], 0 \leq y \leq f(x)$. Namely, we count how many points in the 2d mesh with spacing |
* Let $A(n) = 2^{-2n} N(n)$. Since the area of a $2^{-n} \times 2^{-n}$ square is $2^{-2n}$. | * Let $A(n) = 2^{-2n} N(n)$. Since the area of a $2^{-n} \times 2^{-n}$ square is $2^{-2n}$. | ||
- | Is it true that $\lim_{n \to \infty} A(n) = \int_0^1 f(x)dx$? | + | Is it true that |
+ | $$ \lim_{n \to \infty} A(n) = \int_0^1 f(x)dx ? $$ | ||
+ | To get started, you may assume that $f$ is continuous (we will see next week that continuous functions are Riemann integrable). | ||