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math121b:04-03

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2020-04-03, Friday

Today we consider PDE problem in cylindrical coordinate and spherical coordinate.

Cylindrical Coordinate

Recall that Laplacian in cylindrical coordinate $r, \theta, z$ is written as $$ \Delta u = \frac{1}{r} \d_r(r \d_r(u)) + \frac{1}{r^2} \d_\theta^2 u + \d_z^2 u. $$ We shall look for eigenfunctions of $\Delta$ of the following form $$ u(r,\theta, z) = R( r ) \Theta(\theta) Z(z), $$ Then we have $$ \frac{1}{u}\Delta u = \frac{1}{R} \frac{1}{r} \d_r(r \d_r(R)) + \frac{1}{\Theta} \frac{1}{r^2} \d_\theta^2 \Theta + \frac{1}{Z} \d_z^2 Z. $$ such that $$ \d_\theta^2 \Theta(\theta) = \lambda_\theta \Theta(\theta) $$ $$ \frac{1}{R} \frac{1}{r} \d_r(r \d_r(R)) + r^{-2} \lambda_\theta = \lambda_r $$ $$ \frac{1}{Z} \d_z^2 Z = \lambda_Z. $$

Step 1: Solve the eigenvalue problem for $\Theta$. Since $\Theta(\theta) = \Theta(\theta+2\pi)$, the eigenvalues of $\theta$ are $\sin(n\theta), \cos(n\theta)$ with eigenvalues $\lambda_\theta = -n^2$ for integer $n \geq 0$. More precisely, for $\lambda_\theta=0$, the eigen-space is one-dimensional, and is generated by the constant function $1$; for $\lambda_\theta = -n^2$ for positive integer $n$, we have 2-dimensional eigenspaces $V_{\lambda_\theta}$, generated by $\sin(n\theta), \cos(n\theta)$.

Step 2: Solve the eigenvalue problem for $R( r)$. The eigenvalue problem is $$ \frac{1}{R} \frac{1}{r} \d_r(r \d_r(R)) + r^{-2} (-n^2) = \lambda_r $$ where we plugged in $\lambda_\theta$'s possible values. Re-arranging terms, we get $$ r \d_r(r \d_r(R)) + (-\lambda_r r^2 - n^2) R = 0 $$ Compare with Bessel equation (12.2) from Boas $$ x(xy')' + (x^2 - p^2) y = 0 $$

math121b/04-03.1585882142.txt.gz · Last modified: 2020/04/02 19:49 by pzhou