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math121b:ex2 [2020/02/10 12:57] pzhou created |
math121b:ex2 [2020/02/10 13:00] (current) pzhou |
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====== Solution ====== | ====== Solution ====== | ||
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where we define $\alpha_j = F(t^j)$ for any $j \geq 0$. | where we define $\alpha_j = F(t^j)$ for any $j \geq 0$. | ||
+ | 5. Yes. By definition, $y: V \to \R$ is a function whose image is not just $\{0\}$. Suppose $v \in V$, and $y(v) \neq 0$. We consider the element $w = v / y(v) \in V$. Then | ||
+ | $y(w) = y(v/y(v)) = y(v)/y(v) = 1$. Hence, for any $\alpha \in \R$, we have $\alpha w \in V$, such that | ||
+ | $$\langle \alpha w, y \rangle = y(\alpha w) = \alpha y(w) = \alpha. $$ | ||