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math214:03-04 [2020/03/04 08:44]
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 ====== 2020-03-04, Wednesday ====== ====== 2020-03-04, Wednesday ======
 $$\gdef\T{\mathbb T}$$ $$\gdef\T{\mathbb T}$$
 +
 +===== Definitions =====
  
 A Lie group $G$ is a smooth manifold that is also a group in the algebraic sense, such that the multiplication map $m: G \times G \to G$ and the inverse $i: G \to G$ are all smooth maps.  A Lie group $G$ is a smooth manifold that is also a group in the algebraic sense, such that the multiplication map $m: G \times G \to G$ and the inverse $i: G \to G$ are all smooth maps. 
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 $$ L_g(h) = gh, \quad R_g(h) = hg $$ $$ L_g(h) = gh, \quad R_g(h) = hg $$
  
-==== Example ==== +==== Examples ==== 
    * $GL(n, \R)$, the invertible $n \times n$ matrices with real entries. It's dimension is $n^2$. We can check multiplication is smooth by writing down the formula $C = AB$, then $c_{ij} = \sum_k a_{ik}b_{kj}$. And the inverse is smooth, since we can write $G^{-1} = (\det G)^{-1} G_{adj}$. An open subgroup of $GL(n, \R)$ is $GL_+(n, \R)$.     * $GL(n, \R)$, the invertible $n \times n$ matrices with real entries. It's dimension is $n^2$. We can check multiplication is smooth by writing down the formula $C = AB$, then $c_{ij} = \sum_k a_{ik}b_{kj}$. And the inverse is smooth, since we can write $G^{-1} = (\det G)^{-1} G_{adj}$. An open subgroup of $GL(n, \R)$ is $GL_+(n, \R)$. 
    * $GL(n, \C)$, as a complex manifold.     * $GL(n, \C)$, as a complex manifold. 
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    * Translation group $\R^n$ acting.     * Translation group $\R^n$ acting. 
    * The circle group $S^1 \subset \C^*$.     * The circle group $S^1 \subset \C^*$. 
-   * The n-dimensional torus $\T^n = \S^1 \times \cdots \times S^1$. +   * The n-dimensional torus $\T^n = (\S^1)^n$. 
 +   * Important subgroups of $GL(n, \R)$ and $GL(n, \C)$ (later when we know how to produce subgroups) 
 +     * special orthogonal group $SO(n, \R)$,   
 +     * Lorentz group $SO(1,3)$ ,  
 +     * Symplectic group $Sp(2n, \R) \subset GL(2n, \R)$.  
 +     * Unitary group $SU(n) \subset GL(n, \C)$ 
 + 
 +===== Group Homomorphism ===== 
 +Let $G, H$ be Lie group, we say $\varphi: G \to H$ is a Lie group homomorphism, if it is a smooth map and also a group homomorphism.  
 + 
 +   * $(\R, +) \to (\R_+, *)$, $t \mapsto e^t$.  
 +   * $S^1 \into \C$ 
 +   * Let $V, W$ be vector spaces, viewed as Lie group by translation, then any linear map $V \to W$ is a group homomorphism.  
 +   * $\det: GL(n, \R) \to \R^*$, since $\det(AB) = \det(A)\det(B)$.  
 +   * Let $g \in G$, the conjugation action $Ad_g: G \to G$, $h \mapsto g h g^{-1}$ is a group homomoprhism.  
 + 
 +**Thm **: Group homomorphisms are constant rank maps.  
 + 
 +//Proof//: Let $\varphi: G \to H$ be a Lie group homomorphism. We use left translation to move all the maps on the tangent space $T_g G \to T_{\varphi(g)} H$ back to identity $T_e G \to T_e H$.  
 + 
 +===== Lie Subgroup ===== 
 +A ** Lie subgroup of $G$ ** is a subgroup of $G$ endowed with a topology and smooth structure making it into a Lie group and an immersed submanifold of $G$.  
 + 
 +** Prop 7.11 (Lee) **: Let $G$ be a Lie group and $H \subset G$ a subgroup, which is also an embedded submanifold, then $H$ is a Lie subgroup.  
 + 
 +//Proof//: This uses Corollary 5.30, which says, if $F: M \to N$ is a smooth map, $S \subset N$ an embedded submanifold, and image of $F$ is containedin $S$, then $F$ is a smooth map from $M$ to $S$. Of course, one can use slice chart for embedded manifold to prove this corollary directly, but take a look at theorem 5.29 is also useful. Back to this proposition, we just need to check that the multiplication $m: H \times \to G$ and $i: H \to G$ has image contained in $H$, which is guaranteed by the subgroup condition.  
 + 
 +===== Lie group Action ===== 
 +First, we consider just group action. Let $G$ be a group, $M$ be a set. A left group action is a map  
 +$$ \rho: G \times M \to M, \quad (g, p) \mapsto g \cdot p$$ 
 +such that for all $p \in M$, $g_1, g_2 \in G$,  
 +$$ (g_1 g_2) \cdot p) = g_1 \cdot (g_2 \cdot p) $$ 
 +and  
 +$$ e \cdot p = p. $$ 
 + 
 +A continuous action, or a smooth action is defined the same way, just imposing the corresponding conditions on $G, M$ and the map $G \times M \to M$. 
 + 
 +Right action. And how to translate a right action into a left action. 
 + 
 +Lie group usually arises as 'symmetric group of some structure'. For example, if $V$ is a linear space $GL(V)$ is maps from $V$ to $V$ that preserves the linear structure.  
 + 
 +Some terminologies: suppose $\theta: G \times M \to M$ is a left action of a group $G$ on a set $M$. 
 +  * $\theta_g: M \to M$ is the map $p \mapsto \theta(g,p)$.  
 +  * for any $p \in M$, the **orbit** $G \cdot p$ is the set $\{ g \cdot p \mid g \in G\}$.  
 +  * the **isotropy group** or the **stabilizer** of $p$ is the subgroup $\{g \in G \mid g \cdot p = p \}$, denoted as $G_p$.  
 +  * The action is **transitive**, if for any two points $p,q \in M$, there exists an element $g \in G$, such that $g \cdot p = q$. In other words the map $G \times M \to M \times M$, $(g,p) \mapsto (p,g \cdot p)$ is surjective.  
 +  * The action is free, if the only element of $G$ that fixes some element in $M$ is the identity element, namely if $g \cdot p = p$ for some $p \in M$ then $g = e$. Equivalently, all the isotropy groups are trivial.  
 + 
 +Examples:  
 +  * Lie group acts by conjugation on itself.  
 +  * Lie group acts by left translation on itself.  
 +  * $GL(n, \R)$ acts on $\R^n$, it is transitive. What is the isotropy group of $(1,0,\cdots, 0)$?  
 + 
 +==== $G$-equivariant maps ==== 
 +Suppose $M$ and $N$ are two manifolds where the Lie group $G$ acts on the left. We say a smooth map $F: M \to N$ is $G$-equivariant, if  
 +$$ F(g \cdot p) = g \cdot F(p). $$ 
 + 
 +** Thm (constant rank theorem) (7.25) **: If $M, N$ are smooth manifold with left $G$-action. Suppose $G$ acts on $M$ transitively. Then any equivariant map $F: M \to N$ is constant rank. In particular, if $F$ is a surjection, then it is a submersion, $F$ is an injectiion then it is a an immersion; finally if $F$ is a bijection, then it is a diffeomorphism. ' 
 + 
 +This follows immediately from the global rank theorem, which says, if $F: M \to N$ is constant rank, then $F$ is a surjection implies $F$ is a smooth submersion; $F$ is an injection implies $F$ is a smooth immersion; $F$ is a bijection implies $F$ is a diffeomorphism. Morally, it allows one to upgrade a set-wise statement to a smooth manifold statement with control on the differential of $F$.  
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math214/03-04.1583340277.txt.gz · Last modified: 2020/03/04 08:44 by pzhou