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math214:04-01 [2020/03/31 22:42]
pzhou
math214:04-01 [2020/04/03 14:20] (current)
pzhou
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 +$$ \gdef\vect{\text{Vect}} \gdef\lcal{\mathcal L} \gdef\End{\text{End}} \gdef\Hom{\text{Hom}}$$
 +
 +
 ====== 2020-04-01, Wednesday ====== ====== 2020-04-01, Wednesday ======
 Today and Friday, we will follow Nicolascu's note 3.3, and discuss connection on vector bundle.  Today and Friday, we will follow Nicolascu's note 3.3, and discuss connection on vector bundle. 
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 ==== Connection and Covariant Derivative ==== ==== Connection and Covariant Derivative ====
-$$ \gdef\vect{\text{Vect}} \gdef\lcal{\mathcal L} $$+
 Let $\pi: E \to M$ be a vector bundle. A connection should satisfies the following Let $\pi: E \to M$ be a vector bundle. A connection should satisfies the following
   - Data: $\nabla: \vect(M) \times C^\infty(M, E) \to C^\infty(M, E)$, $(X, \sigma) \mapsto \nabla_X(\sigma)$.    - Data: $\nabla: \vect(M) \times C^\infty(M, E) \to C^\infty(M, E)$, $(X, \sigma) \mapsto \nabla_X(\sigma)$. 
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 $$\nabla: \Omega^0(M, E) \to \Omega^1(M, E). $$ $$\nabla: \Omega^0(M, E) \to \Omega^1(M, E). $$
 In general, we define In general, we define
-$$ \Omega^k(M, E) = C^\infty( \wedge^k(T^*E) \ot E) $$+$$ \Omega^k(M, E) = C^\infty( \wedge^k(T^*M) \ot E) $$
 as $k$-forms with coefficient in $E$.  as $k$-forms with coefficient in $E$. 
  
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 Indeed, this is easy to check Indeed, this is easy to check
 $$ A(f \sigma) = (\nabla^1 - \nabla^0) (f \sigma) = (df - df ) \otimes \sigma + f (\nabla^1 - \nabla^0) (\sigma) = f A (\sigma).$$ $$ A(f \sigma) = (\nabla^1 - \nabla^0) (f \sigma) = (df - df ) \otimes \sigma + f (\nabla^1 - \nabla^0) (\sigma) = f A (\sigma).$$
 +
 +** Prop **: the space of all possible connections on $E$, denoted as $\acal(E)$ is an affine vector space model on $\Omega^1(\End(E))$. 
 +
 +Given the previous propostion, we only need to prove that 
 +  - this space $\acal(E)$ is not empty, and 
 +  - for any $\nabla \in \acal(E)$, $A \in \Omega^1(\End(E))$, $\nabla + A \in \acal(E)$. 
 +
 +The first statement can be shown using partition of unity. The second statement is an easy check. 
 +
 +==== Tensor, Hom and Dual ====
 +Let $E_1, E_2$ be two vector bundles on $M$. Recall that we can define the following 
 +$$ E_1 \ot E_2, \quad \Hom(E_1, E_2) $$
 +as vector bundles on $M$, where  the fiber satisfies $(E_1 \ot E_2)_p = (E_1)_p \ot (E_2)_p$ and $\Hom(E_1, E_2)_p = \Hom( (E_1)_p, (E_2)_p)$. We define the dual bundle of a vector bundle $E$ as $E^\vee := \Hom(E, \underline{\R})$ where
 +$\underline{\R} = \R \times M$ is the trivial bundle. 
 +
 +Suppose $(E_1, \nabla^1)$ and $(E_2, \nabla^2)$ are equipped with connections, we define connection on the tensor and hom bundle as 
 +$$ \nabla( \sigma_1 \ot \sigma_2) = \nabla ( \sigma_1) \ot \sigma_2 + \sigma_1 \ot \nabla (\sigma_2) $$
 +where we omit the superscript on $\nabla$ and we use the identification 
 +$$\Omega^1(M, E_1 \ot E_2) = \Omega^1(M) \ot \Omega^0(M, E_1) \ot \Omega^0(M, E_2),$$
 +where the tensor on the RHS is over $\C^\infty(M)$.
 +
 +Suppose $T \in \Hom(E_1, E_2)$, then we define
 +$(\nabla T)(\sigma_1) = \nabla (T \sigma_1) - T (\nabla \sigma_1).$
 +
 +==== Moving Frame ====
 +Let $M$ be a smooth manifold of dimension $n$, $E$ a rank $r$ vector bundle on $M$ over $\R$. Suppose $(U, (x_1,\cdots, x_n))$ is a coordinate chart on $M$, and furthermore $E|_U$ is trivializable, with a trivialization $(e_\alpha)_{\alpha=1,\cdots,r}$. Then we can write a local section $u \in \Gamma(U, E)$ as 
 +$$ u = \sum_\alpha u^\alpha e_\alpha = u^\alpha e_\alpha,$$
 +using Einstein summation convention. 
 +And we can write
 +$$ \nabla(u) =  \nabla(u^\alpha e_\alpha) = d(u^\alpha) \ot e_\alpha + u^\alpha \ot \nabla(e_\alpha). $$
 +Hence, if we know how $\nabla$ acts on the frame $e_\alpha$, we know how it acts on any sections. We may write
 +$$ \nabla(e_\alpha) = \Gamma^{\beta}_{i \alpha} dx^i \ot  e_\beta$$
 +These coefficients $\Gamma^{\beta}_{i \alpha}$ encodes the data of the connection over $U$.
 +
 +More abstractly, we can say: given a trivilization of $E|_U = U \times \R^r$, we may consider the trivial connection $d_U$ on $U \times \R^r$, then over $U$, we have
 +$$ \nabla|_U = d_U + A_U $$
 +where $A_U \in \Omega^1(U, \End(E))$ is called the ** local ** conection 1-form. 
 +
  
  
math214/04-01.1585719774.txt.gz · Last modified: 2020/03/31 22:42 by pzhou