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Topic: MATHEMATICS (Read 8125 times) |
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DOUBELL
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CAN SOMEONE PROVE BY Mathematical induction that (2r)^3 = 2 (n^2) (n+1)^2 . need help with this one.
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towr
wu::riddles Moderator Uberpuzzler
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Re: MATHEMATICS
« Reply #1 on: Sep 1st, 2011, 8:52am » |
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I think you may have stated the problem incorrectly or incompletely. Since there seem to be no constraints on the values of r and n the two sides are plainly not equal for all values of n and r.
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DOUBELL
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Re: MATHEMATICS
« Reply #2 on: Sep 1st, 2011, 9:11am » |
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it is fact correct since for r=1 the LHs is (2)^3 = 8 AND FOR N =1 THE RIGHT HAND SIDE IS 2(1^2) (1+1)^2= 2 (2)^2 = 8.
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pex
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Re: MATHEMATICS
« Reply #3 on: Sep 1st, 2011, 11:41am » |
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I cannot find any other integer solutions than r=0, n=-1 r=0, n=0 r=1, n=-2 r=1, n=1. I don't see what mathematical induction could have to do with it, except perhaps in proving that there are no other solutions (or that there are, but I missed them).
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ThudnBlunder
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Re: MATHEMATICS
« Reply #4 on: Sep 1st, 2011, 12:22pm » |
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Maybe LHS should be (2n3)
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THE MEEK SHALL INHERIT THE EARTH.....................................................................er, if that's all right with the rest of you.
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pex
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Re: MATHEMATICS
« Reply #5 on: Sep 1st, 2011, 12:31pm » |
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on Sep 1st, 2011, 12:22pm, ThudnBlunder wrote:Maybe LHS should be (2n3) |
| I am impressed by your mind-reading skills!
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ThudnBlunder
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Re: MATHEMATICS
« Reply #6 on: Sep 1st, 2011, 12:42pm » |
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on Sep 1st, 2011, 12:31pm, pex wrote: I am impressed by your mind-reading skills! |
| Thank you, pex. [fingernail_polishing_smiley]
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« Last Edit: Sep 1st, 2011, 4:01pm by ThudnBlunder » |
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THE MEEK SHALL INHERIT THE EARTH.....................................................................er, if that's all right with the rest of you.
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towr
wu::riddles Moderator Uberpuzzler
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Re: MATHEMATICS
« Reply #7 on: Sep 1st, 2011, 12:52pm » |
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Ah, then it makes sense base case, 0..0 (2r)3 = 0 = 2 * 02 * (0+1)2 induction under assumption it's true for every natural number smaller than n: 0..n (2r)3 = {move last term from sum} 0..n-1 (2r)3 + (2n)3 = {invoke induction hypothesis} 2 * n2 * (n-1)2 + 8n * n2 = {regroup terms} 2 * ((n-1)2 + 4n) * n2 = {simplify} 2 * n2 * (n+1)2
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« Last Edit: Sep 1st, 2011, 12:54pm by towr » |
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DOUBELL
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Re: MATHEMATICS
« Reply #8 on: Sep 1st, 2011, 1:52pm » |
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on Sep 1st, 2011, 12:22pm, ThudnBlunder wrote:Maybe LHS should be (2n3) |
| THAT IS IN FACT CORRECT ABOUT THE LEFT HAND SIDE
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Michael Dagg
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Re: MATHEMATICS
« Reply #9 on: Feb 29th, 2012, 9:53pm » |
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Gee. One might ask if induction is valid within an induction argument itself. What you do think?
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Regards, Michael Dagg
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Jack Hadin
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Re: MATHEMATICS
« Reply #10 on: Oct 29th, 2012, 11:13am » |
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I think you have recorded the problem wrongly or perhaps incompletely. Because on a search engine appear to be no constraints throughout the principles of r along with n the two sides tend to be plainly not equal for every one of the principles of n also as r.
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