wu :: forums « wu :: forums - Obfuscated code » Welcome, Guest. Please Login or Register. Sep 23rd, 2018, 8:25pm RIDDLES SITE WRITE MATH! Home Help Search Members Login Register
 wu :: forums    riddles    cs (Moderators: Icarus, ThudnBlunder, william wu, SMQ, Grimbal, towr, Eigenray)    Obfuscated code « Previous topic | Next topic »
 Pages: 1 Reply Notify of replies Send Topic Print
 Author Topic: Obfuscated code  (Read 19212 times)
-D-
Guest

 Obfuscated code   « on: Aug 6th, 2002, 11:35am » Quote Modify Remove

The code isn't so obfuscated when it's written like PROPER code....

#include <stdio.h>
#define _ F-->00 || F-OO--;
void F_OO();
long F=00,OO=00;
void main()
{
F_OO();
printf("%1.3f\n", 4.0*-F/OO/OO);
}
void F_OO()
{
...
}

This is pretty much the first 3 lines expanded.

The #define is a macro that defines the _ character.  But it is only expanded for cases where the _ isn't used in a label (such as it is used in F_OO ).

F_OO is actually a function that uses long drawn out operation on F and OO to make them become -202 and -16 respectively.

4 * -202 / -16 / -16 = 3.156 which is what is printed out.  The 4. in the given code is really 4.0.  the - sign is actually a unary minus making the -202 into 202, it doesn't do a subtraction.  It wouldn't have been as obfuscated if it had been written -4.*F/OO/OO see?

So, the code calls the F_00 function to change the values of F and OO, then prints out some math mangling of those values.

The last thing that makes this code more complicated is that they didn't declare their return types for F_OO or main and attempted to assume then as void (which is invalid, proper C would default them to integers).  I'll ignore errors associated with not declaring includes or function prototypes and assume those were just not put in the excerpt.
-D-

 IP Logged
anton
Guest

 Re: Obfuscated code   « Reply #1 on: Dec 25th, 2004, 12:28am » Quote Modify Remove

Since 4.*-F/OO/OO results in an approximation of Pi, we get:
Pi = -4F/OO2
Pi*(OO/2)2 = -F

It makes sense to assume that OO is the diameter of a circle, and F is its area (negative). The circle is actually the one "drawn" in the function F_OO(). Later, I will replace F with a and OO with d.

Let's see what happens in the F_OO function. Each line consists of "_" followed by a string of "-_". Each "_" is replaced with "a-->0 || a-d--;" which means following:
• Subtract one from a. (a--)
• If, before the subtraction, a was negative then perform "a-d--", since the operator || executes its right part only when the left part is false. The meaningful action here is only "d--"; that is, subtract one from d.

The underscore in each "-_" is replaced with the same thing; the only difference is the initial minus sign. Now -a is compared with zero; since -a is always positive, the second part never gets executed.

And now we get the full picture: each of "_" and "-_" decreases a by one; thus, a contains the negative area of the circle. In addition, each initial "_" decreases d by one - in the end d becomes equal to the negative height of the circle, which is the same as its diameter.
 IP Logged
Paul
Newbie

Posts: 1
 Re: Obfuscated code   « Reply #2 on: Apr 6th, 2013, 10:07pm » Quote Modify

People keep showing fractions of pi.You all need to realise pi is a whole number and the rest of the numbers are the fractions.Point then nonpoint.The nonpoint should be a whole number?Ok,seems right doesn't it?
 IP Logged
 Pages: 1 Reply Notify of replies Send Topic Print

 Forum Jump: ----------------------------- riddles -----------------------------  - easy   - medium   - hard   - what am i   - what happened   - microsoft => cs   - putnam exam (pure math)   - suggestions, help, and FAQ   - general problem-solving / chatting / whatever ----------------------------- general -----------------------------  - guestbook   - truth   - complex analysis   - wanted   - psychology   - chinese « Previous topic | Next topic »