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Topic: Mechanical Pendulum Gear Clocks, Hands (Read 9431 times) 

rloginunix
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Mechanical Pendulum Gear Clocks, Hands
« on: Jul 23^{rd}, 2015, 5:05pm » 
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Mechanical Pendulum Gear Clocks Hands 1) Rolling Surfaces 2) Tooth Profiles 3) Gear Trains 4) Hunting Tooth 5) Procedure 6) Second Hand 7) Minute Hand 8) Hour Hand 9) Coaxal Hands 10) Software 11) Literature Rolling Surfaces In the Pendulum chapter we have learned how to calculate the length of a pendulum's rod L for a given period T. In the Escapement chapter we have learned how to harness the back and forth motion of a pendulum and convert it into a predictable circular motion of a special, escape, wheel. In this chapter we will investigate how to complete a clock's design by adding the hands to it. An addition of the hands to a clock can be reduced to an addition of the corresponding gear trains to it. A gear train is a collection of two or more gears so before deep diving into the trains let us look at their atomic unit  a pair of meshing gears. Note that as a historic heritage large gears are called wheels and their teeth are called teeth. Small gears are called pinions while their teeth are called leaves. However, everything that follows is applicable to wheels and pinions and teeth and leaves in equal measure. Two rigid surfaces rolling without slipping is the underlying requirement for a large class of gears including the ones of interest to us  spur gears. For two arbitrary rigid surfaces to roll without slipping two conditions must be met: 1) Their point of contact must be on the straight line connecting the centers of rotation of each surface called a Line of Centers or a Center Line, the straight line O_{1}O_{2} in the drawing below. 2) The projections of the linear velocities and accelerations of both surfaces at the point of contact on a tangent common to both surfaces must be equal in magnitude and same in direction. The last requirement by itself does not impose any additional constraints on linear velocities  it only states that at any instance the two must be equal in magnitude and same in direction. Since acceleration captures the change of velocity over time its presence in the constraint tells us that velocities may change but they must do so in unison. In other words the velocity ratio may vary or remain constant. From this point on we will only consider a constant velocity ratio. Even though the above rule can be applied to arbitrary rigid surfaces we will only consider the spur gears based on right circular cylinders or simply cylinders. Let C_{1} and C_{2} be two such cylinders rolling without slipping. Further, let the axes of rotation of C_{1} and C_{2} be parallel and remain at the same distance from each other at all times: Imagine now that the instantaneous point of contact K splits in two as the surfaces turn. The point K_{1} will then travel along the circumference of C_{1} while K_{2} will travel along the circumference of C_{2}. In a given amount of time K_{1} will trace the arc KK_{1} while K_{2} will trace the arc KK_{2}. The second requirement of the equality of linear velocities' projections means that even though the angle swept by each point may be different the lengths of both (highlighted) arcs must be the same: v_{1} = _{1}R_{1} = _{2}R_{2} = v_{2} (h.1) _{1}/_{2} = R_{2}/R_{1} = const (h.2) where designates an angular velocity. The equation (h.2) tells us that in the case of a constant linear velocity ratio for two cylinders to roll without slipping the ratio of their angular velocities must remain constant as well. Bare cylinders do not transmit torque and keep a constant angular velocity ratio at the same time too well that is why they are given teeth. The teeth are placed on a cylinder in such a way that some portion of them, called a face, protrudes beyond and some portion, called a flank, is submerged below the circumference of the generating cylinder. The radial height of a face is called an addendum and the radial height of a flank is called a dedendum. In the above manner we can construct two gears which when engaged have the angular velocity ratio equal to that of two rolling virtual or generating cylinders. Such cylinders are called Pitch Cylinders. A circle obtained by cutting a pitch cylinder with a plane perpendicular to its axis of rotation is called a Pitch Circle. The radius of a pitch circle is called a Pitch Radius and the diameter of a pitch circle is called a Pitch Diameter. A circle concentric with the pitch circle passing through the tips of the gear's teeth is called an Addendum Circle or an Outer or a Tip circle. A circle concentric with the pitch circle passing through the roots of the gear's teeth is called a Dedendum Circle or a Root Circle. Hopefully these definitions that I gave in the Escapement chapter are more understandable now. Euclid's Elements Book 3 Proposition 13 states that a circle does not touch another circle at more than one point whether it touches it internally or externally. This single point of tangency of two pitch circles is called a Pitch Point. From Book 3 Propositions 11 and 12 it follows that for two gears engaged either externally or internally the pitch point is always located on the line of centers. A straight line perpendicular to a tangent common to two tooth profiles at the point of their contact, a normal, is called a Line of Action. Earlier we have established that from the requirements imposed on two rolling smooth rigid surfaces it follows that for two gears to mesh their angular velocity ratio must remain the same. This is the basic law of gearing which is obeyed when at any point of contact of two gears the line of action and the line of centers intersect at the pitch point.


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rloginunix
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Re: Mechanical Pendulum Gear Clocks, Hands
« Reply #1 on: Jul 23^{rd}, 2015, 5:07pm » 
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Two more parameters must be the same for two gears to mesh  an Angle of Pressure and a Pitch of a gear. An angle of pressure or simply a pressure angle is an angle between the line of action and the tangent common to both pitch circles. Two popular pressure angles are 14.5 and 20 degrees. The larger the pressure angle the thicker the root of the tooth is  the more load it can bare and conversely. A pitch of a gear is a numeric characteristic of the density of the gear's teeth distribution over the circumference of the root circle. Density is usually a ratio of a number or an amount of units of interest to some spacial measure. For example, a linear density tells us how mass is distributed over a massive line segment in one dimension. A square density tells us how mass is distributed over a thin disk (circle) in two dimensions. A volume density tells us how mass is distributed inside a solid sphere in three dimensions and so on. For a gear its pitch tells us how large the teeth and the spaces between them are. In our case all the teeth of a standard spur gear have the same size, the same amount of space between them and the same distance from the axis of rotation  in other words these teeth are distributed uniformly over the circumference of the root circle and their count is always a whole number. Imagine two such gears of equal radii one with 20 and the other with 40 teeth. Without any formulas it should be intuitively clear that the teeth and the spaces between them on the first gear should be larger than their counterparts on the second gear and conversely. Three basic magnitudes are used to describe the dental density of a gear  a Circular Pitch, a Diametral Pitch and a Module or Modulus. A Circular Pitch or cp for short is an absolute linear magnitude equal to the distance between the same points on the profiles of two adjacent teeth measured along the circumference of the pitch circle. From the above observation of uniform teeth distribution and the fact that the tooth count of a standard gear is always integral (a whole number) it follows that a gear that has N teeth also has N arcs each of which is equal to one circular pitch. If the angle of one such arc is measured in radians by definition we have: cp = R (h.3) and N such arcs complete the entire circle: cp = R2/N = D/N (h.4) where R and D are pitch radius and diameter. A circular pitch can be expressed in either Imperial units, inches, or in metric units, millimeters. A Diametral Pitch (not to be confused with pitch diameter) or dp for short is a relative magnitude equal to the number of teeth N divided by the pitch diameter D: dp = N/D (h.5) Though technically it does not have to be diametral pitch is usually associated with the Imperial system in terms of which it is a number of teeth of a gear per one inch of its pitch diameter. A diametral pitch can be expressed in either inverse Imperial or inverse metric units. Since D is a common term between (h.4) and (h.5) it follows that: D = (N*cp)/= N/dp = D (h.6) dp*cp = (h.7) A Module or m for short is a relative magnitude equal to the pitch diameter D divided by the number of teeth N: m = D/N (h.8) Though technically it does not have to be Module is usually associated with the Metric system. In either system Module is the length of a pitch diameter per one tooth. A Module can be expressed in either metric or Imperial units. If the same units are used for diametral pitch and module then the two are just the inverses of each other. Now that we have three different ways of dealing with essentially the same thing which one should be used? In theory it does not matter  with the following relationship: 1 inch = 25.4 mm (h.9) we know how to convert inches to millimeters and vice versa and with the above formulas given one dental density magnitude we can always obtain the other two. So theoretically even if you mix and match the systems within one project the end result should come out right  the only difference being the ugliness or nicety of the actual values. With the Imperialoriented diametral pitch the inch values will be nice and round or close to it while the millimeter values will likely be ugly and awkward. And conversely  with the metricoriented Module the millimeter values will be nice and round or close to it while the inch values will likely be ugly. The practice, however, begs to differ. Not only the software and the hardware tools which you will use to generate and cut the gear profiles will pick the units of measurement for you  these units should really be the same, all Imperial or all Metric. As long as the meaning of the terms used is understood the desirable results can be achieved regardless of the unit system employed. It may also be a good idea to capture the entire design of a clock in a number of key characteristics of lengths, tooth counts, diameters and train ratios and save it for future reference. Once the number of teeth and pitch diameters of two gears are decided on the distance between their axes can be calculated. In terms of pitch radii R_{1} and R_{2}, or pitch diameters D_{1} and D_{2}, or tooth counts N_{1} and N_{2} and either Diametral Pitch dp or Module m it is: O_{1}O_{2} = R_{1} + R_{2} (h.10) O_{1}O_{2} = (D_{1} + D_{2})/2 (h.11) O_{1}O_{2} = (N_{1} + N_{2})/2dp (h.12) O_{1}O_{2} = (m(N_{1} + N_{2}))/2 (h.13)


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rloginunix
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Re: Mechanical Pendulum Gear Clocks, Hands
« Reply #2 on: Jul 23^{rd}, 2015, 5:09pm » 
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Tooth Profiles A tooth profile is generally a plane curve used to delineate the shape of a tooth in the plane of the gear's face. To reveal the tooth profile of a given gear the name of the curve is inserted in front of the word gear as in cycloidal gear or involute gear. Though in theory we can use any goofy tooth profile for two gears to kind of turn and sort of work in practice their choice is limited. In so many words in "The Science of Clocks and Watches" A. L. Rawlings outlines the following requirements on practical tooth profiles at the industrial scope: 1) constant angular velocity ratio, 2) manufacturability of mathematically precise shapes, 3) interchangeability of gears across all tooth counts of the same pitch, 4) axes distance deviation tolerance, 5) axes should not be pushed apart, 6) post line of centers action. In the early days a cycloid was a curve of choice. From the Pendulum chapter we remember that a cycloid is a plane curve traced by a point on a circumference of a circle rolling along a stationary straight line without slipping. These cycloidal gears worked well in clocks where the speeds of rotation are low and the loads are light. Later on it was discovered that the cycloidal gears do not scale well to the industrial machinery where the speeds of rotation are much higher and the loads are much heavier. A number of new tooth profiles that dealt with the new requirements better were employed, including an involute of a circle. An involute of a circle is a plane curve traced by a point at the end of a taut string as it unwinds off of or winds around a circumference of a stationary circle. Put it another way an involute of a circle is a plane curve traced by a point on a straight line rolling along the circumference of a stationary circle without slipping. The above gear requirements are satisfied by an involute of a circle but it does not mean that we must use it because some of these points are moot due to the peculiarity of our process  we will be cutting our own gears which will turn slowly under light loads. One of the practical benefits of the involute gears is that they tolerate small deviations from the calculated distance between their centers O_{1}O_{2} much better than the cycloidal gears do. If your actual distance O_{1}O_{2} is a little off then the involute gears will still have a constant angular velocity ratio while the cycloidal gears will not  the actual distance between their centers must be kept exactly at O_{1}O_{2}. On the other hand the cycloidal gears generate less sliding friction resulting in less wear and tear, for proper operation they can have less teeth per given size and consequently they can be used to achieve higher ratios with less gears. Bottom line  experiment! Gear Trains Now that we know a little bit about how one pair of gears operates we can string together any number of such pairs into a gear train with a purpose of converting a given input into a desired output. A desired output could be a change in direction or rate of rotation, for example, or both. We observe here that two gears meshing externally rotate in the opposite direction while two gears meshing internally rotate in the same direction. Moreover, if the number of the externally meshing gears is even then the output (last) gear in such a train will rotate in the direction opposite to that of the input gear. If the number of such gears is odd then the direction of rotation of the output and the input gears is the same. This observation is of importance if we want all the hands on a clock's face to rotate in the same direction. From the Escapement chapter we remember that a gear to which power is applied directly is called a driver or an input gear while the gear which is affected by it is called a driven or a follower or an output gear. A gear ratio of a pair of gears then is the ratio of angular velocities of the corresponding pitch cylinders: r_{i,o} = _{i}/_{o} = R_{o}/R_{i} = N_{o}/N_{i} where the sub index i stands for Input and o for Output, R designates a radius and N designates a tooth count. The reason we can relate a radius of a gear to its tooth count is because all the teeth on our gears are equally sized and uniformly distributed as was noted above. We can roughly classify gear trains based on the number of engaged gears per axis. We can have trains with a single gear per axis or multiple gears per axis. When forming the pairs in a single gear per axis train the output gear of the current pair and the (logical) input gear of the next pair are one and the same. In the sample drawing below the first pair is the gears G_{1} and G_{2}, G_{1} being an input gear. The second pair is the gears G_{2} and G_{3}, G_{2} being a logical input of this pair: The consequence of such an arrangement is that it does not work too well for high gear ratios but it is suitable for situations when power has to be transmitted over a large distance. To understand why let us conduct the following experiment. Let us assume that we need a gear train with a 1,000:1 gear ratio. Let us assume that our input gear has 30 teeth. Though theoretically it is and even technologically it may be possible to achieve any required ratio with just two gears it is simply impractical to do so in most cases. As such we rule out connecting a 30,000tooth output gear to a 30tooth input gear. We then factorize 1,000 as 10*10*10, for example, hoping to achieve a manageable tooth count for the intermediate gears and add one gear to the train per factor. Let us see where it takes us. The second gear in our train must have 30*10 = 300 teeth, the third gear must have 300*10 = 3,000 teeth while the fourth gear must have 3,000*10 = 30,000 teeth still! So between 4 wheels we have a total of 33,330 teeth and impractical per gear tooth counts. Further, no matter how we factorize 1,000 the tooth count for the last wheel will always be unmanageable. For 1,000 = 2*5*2*5*2*5 we get the following tooth counts: 60, 300, 600, 3,000, 6,000 and 30,000 or a total of 7 wheels and 39,990 teeth and so on. What is going on here?


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rloginunix
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Re: Mechanical Pendulum Gear Clocks, Hands
« Reply #3 on: Jul 23^{rd}, 2015, 5:10pm » 
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Let us say we have four gears in our train  an input gear G_{1} and three more gears connected edge to edge  G_{2}, G_{3} and G_{4}. The ratio between the first two pairs, G_{1} and G_{2}, and G_{2} and G_{3}, is: r_{1,2} = _{1}/_{2} (h.14) r_{2,3} = _{2}/_{3} (h.15) The gear ratio between G_{1} and G_{3} by definition then is: r_{1,3} = _{1}/_{3} (h.16) which can be rewritten as: r_{1,3} = _{1}/_{3} = _{1}/_{2} * _{2}/_{3} = r_{1,2} * r_{2,3} (h.17) In a similar manner for gears G_{1} and G_{4} we get: r_{1,4} = _{1}/_{4} = _{1}/_{2} * _{2}/_{3} * _{3}/_{4} = r_{1,2} * r_{2,3} * r_{3,4} (h.18) In other words a gear ratio of a train is a product of the ratios of its intermediate pairs: r_{1,N} = r_{i  1, i} (h.19) where i runs from 2 to N. If in (h.18) we replace the angular velocities with the corresponding tooth counts then for this particular type of train the intermediate tooth counts will cancel each other out: r_{1,4} = N_{2}/N_{1} * N_{3}/N_{2} * N_{4}/N_{3} = N_{4}/N_{1} (h.20) And since the intermediate gears do not contribute to the grand total they are called idlers and we see why for high gear ratios the last gear in the train has an impractical tooth count. Now instead of just one let us attach two gears to the same axis  one large gear, a wheel, and one small gear, a pinion. Since both gears are attached to the same axis their angular velocities  angles swept per unit of time  are the same. Which means that by the time the wheel makes one full turn  so does its coaxal pinion even though it has a lower tooth count: In this arrangement we make a pinion a logical input gear and a wheel (on a different axis) an output gear. Let us say that we attach the 7leaf pinions to each wheel and use a 10:1 gear ratio for each pair. Then the third gear or the second wheel must have 7*10 = 70 teeth. The fifth gear or the third wheel must also have 70 teeth and so does the seventh gear of the fourth wheel. Now between 7 gears and only 270 teeth we have achieved the required gear ratio and manageable per gear tooth counts. Compare 270 and 39,990  clearly our two gears per axis train has an advantage  less teeth and a smaller space requirement. Since in this types of trains the output gear of the previous pair (W_{2} in the drawing above) is different from the input gear (P_{2}) of the current one the tooth counts do not cancel out and the ratio of a train is the product of the ratios of tooth counts of all the intermediate pairs. If we designate the tooth counts of the wheels with w and the tooth counts of the pinions with p then the ratio of this type of a train is: r_{1,N} = w_{1}/p_{1} * w_{2}/p_{2} * ... * w_{N}/p_{N} = w_{i}/p_{i} (h.21) where i runs from 1 to N.


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rloginunix
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Re: Mechanical Pendulum Gear Clocks, Hands
« Reply #4 on: Jul 23^{rd}, 2015, 5:16pm » 
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Hunting Tooth We know that a gear ratio is formed by two whole positive integers each of which represents a tooth count. Let gear G_{1} have N_{1} teeth and gear G_{2} have N_{2} teeth. Let us temporarily straighten both gears into Nx1 blocks along a number line, join them face to face and designate each tooth with a square. In the drawing below we see a case where N_{1} = 3 and N_{2} = 5: It should be fairly obvious that a tooth a of G_{1} and a tooth b of G_{2} that are in contact in the initial configuration will come into contact again lcm(N_{1}, N_{2}) squares later, where lcm is the Least Common Multiple  a smallest integer evenly divisible by N_{1} and N_{2}. In the drawing above a and b will kiss every 15 squares. Here we can introduce the concept of a Mating Length (ml)  the smallest number of teeth between the rendezvous points of two mating teeth or numerically: ml = lcm(N_{1}, N_{2}) (h.22) To translate the Mating Length measured in teeth into the number of Mating Steps (ms) of each gear we then simply divide ml by the number of teeth of each gear: ms_{1} = ml/N_{1} (h.23) ms_{2} = ml/N_{2} (h.24) For G_{1} we get 15:3 = 5 full steps and for G_{2} we get 15:5 = 3 full steps along the number line. The reason we assured that ms is always an integer is because of the basic number theoretic theorem which states that for any two positive integers N_{1} and N_{2}: lcm(N_{1}, N_{2}) * gcd(N_{1}, N_{2}) = N_{1} * N_{2} (h.25) where gcd() is the Greatest Common Divisor  the largest common factor of N_{1} and N_{2}. If we divide both sides of the above equation first by, say, N_{2} and then by gcd() we get: ml/N_{2} = N_{1}/gcd(N_{1}, N_{2}) (h.26) By definition of gcd() N_{1} = gcd(N_{1}, N_{2}) * m, where m is some integer. Putting it back into (h.26) the gcd()s cancel out while the integer m remains. Now if we make our gears round again, replace steps with revolutions and replace the Mating Steps with the Mating Period (mp)  the number of revolutions of one gear after which one of its teeth finds its mate on the other gear  then: mp_{1} = ml/N_{1} (h.27) mp_{2} = ml/N_{2} (h.28) Divide (h.27) by (h.28): mp_{1}/mp_{2} = N_{2}/N_{1} = p/q = r_{1,2} (h.29) where the above gear ratio is represented in its standard form p:q, p and q being relatively prime (meaning their greatest common divisor is one). From this we conclude that: once we lock two gears into their positions the same teeth on both gears will mate every p full revolutions of G_{1} and q full revolutions of G_{2} We then can distinguish three cases. 1) N_{1} and N_{2} are relatively prime to begin with (p = N_{2}, q = N_{1}). In ths case the mating period of one gear is simply the number of teeth on the other gear. For a 17tooth input gear meshing with a 35tooth output gear the same teeth will mate every 35 revolutions of the 17tooth gear and every 17 revolutions of the 35tooth gear. Purely for reference sake let us call this type of ratios relatively prime. 2) N_{1} and N_{2} are not relatively prime but neither p nor q is 1. For a 21tooth input gear meshing with a 35tooth output gear their ratio is 5:3 and the same teeth for this pair will mate every 5 revolutions of the 21tooth and every 3 revolutions of the 35tooth gear. Let us call this type of ratios nonwhole. 3) Either p or q is 1. For a 30tooth input gear meshing with a 60tooth output gear their ratio is 2:1 and the same teeth for this pair will mate every 2 revolutions of the 30tooth gear and every 1 revolution of the 60tooth gear. Let us call this type of ratios whole. Quite often N_{2} and N_{1} can be made relatively prime simply by an addition of just one tooth to one of the wheels. If in our last case we add one tooth to the output 60tooth gear then the ratio becomes 61:30 or relatively prime. It means that the same teeth on both gears will mate every 61 revolutions of the 30tooth gear and every 30 revolutions of the 61tooth gear. Comparing the frequencies of tooth mating for various gear ratios we conclude that: if the ratio of two ingaged gears G_{1}(N_{1}) and G_{2}(N_{2}) is expressed in a standard form of p/q then the larger p and q are the less frequently the same teeth of G_{1} and G_{2} mate and conversely If we look back at the drawing above it may be said that a and b are engaged in a periodic process of hunting for each other during which they come into contact, diverge and then find each other again. Possibly because of this association the extra tooth that lengthens the above mating interval was named a hunting tooth. Its addition to one of the gears will obviously change the ratio of a pair and of the entire train of which this gear is part of. While some mechanisms can tolerate such usually small change without ill effects the clocks normally can not. As such we must incorporate the concept of a hunting tooth into our gears with care.


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rloginunix
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Re: Mechanical Pendulum Gear Clocks, Hands
« Reply #5 on: Jul 23^{rd}, 2015, 5:18pm » 
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The rationale behind the hunting tooth is the desire to even out the wear and tear of imperfectly manufactured gears. The hope here is that the lifetime and the operation of gears will benefit if the effect of an imperfection of a tooth is spread across multiple teeth thus avoiding a constant wear inflicted on the same tooth. Let us look at a realistic example. Let us assume that in this particular clock we have decided to have a second hand and we already have a 30tooth wheel that makes one full revolution in one minute. Our minute train then has to have a 60:1 ratio. We factorize 60 as 6*10, to the axis of the 30tooth second wheel we attach an 11leaf pinion which we mesh with a 66tooth wheel for a 6:1 ratio. To the axis of the 66tooth wheel we attach a 9leaf pinion which we mesh with a 90tooth wheel for a 10:1 ratio making the total ratio of the entire train 60:1 as required. With this configuration the same teeth of the first pair mate every 6 full revolutions of the pinion and every one full revolution of the wheel while the same teeth of the second pair mate every 10 full revolutions of the pinion and every one full revolution of the wheel. Let us see if we can decrease these frequencies. Since multiplication of two integers is commutative we can swap the order of factors without changing the result: r_{m} = 66/11 * 90/9 = (66*90)/(11*9) = (90*66)/(11*9) = 90/11 * 66/9 In this new arrangement the 11leaf pinion is meshed with the 90tooth wheel yielding a 90:11 ratio which can not be reduced any further and the 9leaf pinion is meshed with the 66tooth wheel yielding a 66:9 ratio which can be reduced to a 22:3 form. The overall ratio of the minute train is still 60:1 as required but the same teeth of the first pair of gears mate every 90 full revolutions of the pinion and every 11 full revolutions of the wheel while the same teeth of the second pair mate every 22 full revolutions of the pinion and every 3 full revolutions of the wheel. Even though we did not use a hunting tooth per se we achieved a decrease in mating frequencies simply by swapping the order in which the wheels and their pinions mesh. Confirm this by calculating the corresponding lcm()s. More nonwhole ratios can either be found by hand or with computer software. At the end of this chapter I list a C source code for a few simple computer programs to print out the wheel and pinion tooth counts for whole and nonwhole ratios, relatively prime tooth counts and factorizations of an integer. Keep in mind that the idea of a hunting tooth should likely be treated as a mathematical curiosity which is fun to implement and not as a serious weapon against gear manufacturing defects since we are in full control of making of our own gears (which turn slowly under light loads). Procedure In the Escapement chapter we observed that it is possible to drive the design of a clock by a number of parameters. I will not be covering all the possibilities here but will instead concentrate on the most likely 1230 candidate  a clock with a 1meter pendulum that has a 2second period and a 30tooth escape wheel. You should have no problems adjusting what follows to some other design variation. 1) Given the 2second period and a 30tooth escape wheel the latter will make one full revolution in one minute. Attach a second hand to the axis of the escape wheel if desired. 2) The minute train driven by the escape wheel then should have a 60:1 ratio while the hour train driven by the last gear of the minute train should have a 12:1 ratio. Name either ratio r. 3) Factorize r: r = f_{1} * f_{2} * ... * f_{n}. Normally you would start with just two factors. If you want to reduce the size of the gears  add more. 4) For each factor f_{i} make two gears  a p_{i}leaf pinion and a w_{i}tooth wheel. For a minute train then we will have 4 gears and for the hour train we may have either also 4 gears (for 8 + 1 = 9 gears total) or just 2 gears  if we decide to implement the 12:1 ratio directly (for 6 + 1 = 7 gears total). 5) For a pinion pick p_{i} as some small integer at will. In "The Science of Clocks and Watches" A. L. Rawlings mentions 11 as a reasonable minimum but (of course) do experiment with a lower number. 6) To decide on the value of w_{i} decide on the ratio factorization type. Some (but not all) choices are:  all the factors are whole  none are whole  some are whole and some are not More on this below. If using the whole gear ratios then make w_{i} = f_{i} * p_{i}. If using the nonwhole gear ratios (including the relatively prime ones) then pick w_{i} in such a way that the product of all the w_{i}/p_{i} ratios yields the train's ratio r. 7) Attach the pinion to the axis of the output wheel of the previous pair. Mesh that pinion with its wheel. 8) Make the last wheel of the current train coaxal with the last wheel of the previous train if desired. 9) Attach the corresponding hand to the last wheel of the train.


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Re: Mechanical Pendulum Gear Clocks, Hands
« Reply #6 on: Jul 23^{rd}, 2015, 5:20pm » 
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Second Hand Since the number of distinct hands is 3  second, minute, hour  the total number of subsets in this set is 2^{3} = 8  meaning there are a total of 8 possible ways to mix and match the hands in a clock from a design perspective: 1) no hands 2) second hand 3) second and minute hands 4) second and hour hands 5) second, minute and hour hands 6) minute hand 7) minute and hour hands 8) hour hand I will not be commenting on the usefulness of any of the above choices  that is up to the author(s) to decide. In the discussion below I will only cover the most popular second, minute, hour hands configuration. For a clock to have a second hand it must have at least one gear that makes one full revolution per minute. Quite often an escape wheel does exactly that and it is only logical that we attach the second hand directly to it. Keep in mind that the tip of the second hand may or may not fall exactly on a onesecond/oneminute gradation mark with each move of the wheel or with each beat of the pendulum. From the Escapement chapter, however, we remember that in a 2second 30tooth escape wheel clock it will. In any case, when designing your own DIY clock with a second hand it would make sense to choose the period T and the escape wheel tooth count N_{ew} such that T * N_{ew} = 60. Minute Hand For a clock to have a minute hand it must have at least one gear that makes one full revolution per hour. If we already have a gear that makes one full revolution per minute then we can use it to drive the minute train. As such we have to slow down the last gear of the second train 60 times. Therefore the ratio of this minute train should be 60:1. We factorize that ratio as 6*10, for example. Using the software at the end of this chapter we, for example, pick two pairs of relatively prime tooth counts for that factorization: 54:11 and 110:9. To the axis of the one full revolution per minute gear we attach, say, the 11leaf pinion which we mesh with the 54tooth wheel. To the axis of the 54tooth wheel we attach the 9leaf pinion which we mesh with the 110tooth wheel. Lastly, we attach the minute hand to the axis of the 110tooth wheel which will make one full revolution every hour. We may also factorize 60 as 5*12 and make all the factors whole  as in 35:7 and 108:9, or make all the factors not whole  as in 35:10 and 120:7, mix the factor types  as in 96:12 and 120:16 and so on. If we decided to not have a one full revolution per minute gear in this particular clock then we can drive the minute train with the escape wheel. In that case the ratio of the minute train will be determined by the rate of turn of the escape wheel. For example, let us assume that we are designing a 2second clock with a 77tooth escape wheel which makes one full revolution in 77*2 = 144 seconds. Since there are 3,600 seconds in one hour this escape wheel will make 3,600:144 = 25 revolutions during that period of time. Therefore the train ratio we need is 25:1. It is of course an overkill but for demonstration purposes using the same software we factorize that ratio as 5*5 and then feed these factors into the program that will give us the corresponding tooth counts. Say we pick two pairs of relatively prime counts of 55:9 and 45:11 and proceed as in the previous paragraph  to the axis of the 77tooth escape wheel we attach the 9leaf pinion which we mesh with the 55tooth wheel so on. As we can see not only the software comes in handy but more importantly the number of design possibilities  gear configurations  is quite considerable. Hour Hand For a clock to have an hour hand it must have at least one gear that makes one full revolution every 12 hours. If we already have a gear that makes one full revolution every hour we can use it to drive the hour train. As such we have to slow down the last wheel of the minute train 12 times. Therefore the ratio of this hour train should be 12:1. We may factorize that ratio as 3*4, for example, and use the software to print out all the relatively prime pairs for these factors. We pick 27:11 and 44:9, for example. To the axis of the one full revolution per hour gear we attach the 11leaf pinion which we mesh with the 27tooth wheel. To the axis of the 27tooth wheel we attach the 9leaf pinion which we mesh with the 44tooth wheel. We attach the hour hand to the axis of the 44tooth wheel which will make one full revolution every 12 hours. We may also choose to implement the 12:1 ratio directly  with just two gears: an 8leaf pinion and a 96tooth wheel or a 9leaf pinion and a 108tooth wheel and so on. If we do not have a gear that makes one full revolution every hour then it would make sense to select the slowest available gear and design an appropriate hour train for it. Coaxal Hands If we want to make the last two pinion/wheel pairs of two trains coaxal we observe that the sums of the corresponding pitch circles' radii must be equal. Let G_{1} be a pinion with the radius R_{1} attached to, say, the axis of the escape wheel which makes one full revolution per minute and our objective is to have coaxal second and minute hands. Let G_{2} be a gear with the radius R_{2}. Let G_{2} mesh with G_{1} to produce some needed ratio, say 10: To complete the minute train we need another pair of gears, a pinion G_{3} with the radius R_{3} and a wheel G_{4} with the radius R_{4}, which when meshed produce another needed ratio, say 6. We then need to design G_{1}, G_{2}, G_{3} and G_{4} in such a way that their respective pitch radii satisfy the following relationship: R_{1} + R_{2} = R_{3} + R_{4} [e]Fixed silly Minute/Hour train typos[/e]

« Last Edit: Jul 25^{th}, 2015, 10:53am by rloginunix » 
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rloginunix
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Software The attached file contains the C code for six (no warranties) programs which print out  1) factors of given positive integers, 2) whole clock gear ratios, 3) nonwhole clock gear ratios, 4) relatively prime clock gear ratios, 5) greatest common divisor and 6) least common multiple of two positive integers. The file also contains the instructions on how to build these programs and run them. The intended usage of this tiny collection of programs is as follows. While designing a clock gear ratios inevitably enter the picture. The procedure to design a gear train for a given ratio is described above. This procedure starts out with a factorization of a given ratio. According to the fundamental theorem of arithmetic any number greater than 1 is either prime or can be represented as a unique product of primes if their order is ignored. In clock gear ratios, however, a representation condensed to just two factors is of most popular interest. That is why the first program prints these out in the p*q format. If more than twofactor products are needed then simply pick any one factor and feed it to the program again: ./f 60 60: 1 x 60 2 x 30 3 x 20 4 x 15 5 x 12 6 x 10 Pick a pair out of the list: 5*12, for example. Next, decide on the type of the ratio  whole, nonwhole, relatively prime. To print all the whole ratios use the wcgr program: ./wcgr 5 12 5:1 ratios: 25:5 30:6 35:7 40:8 45:9 50:10 55:11 60:12 65:13 70:14 75:15 80:16 85:17 90:18 95:19 100:20 105:21 110:22 115:23 120:24 125:25 130:26 135:27 140:28 145:29 150:30 12:1 ratios: 60:5 72:6 84:7 96:8 108:9 120:10 132:11 144:12 In this case it is safe to pick any ratio from one set and use it with any ratio from the other set. I have limited the number of teeth in these ratios to 5 as the smallest and 150 as the highest, feel free to change them. To print all the nonwhole ratios, which will include the relatively prime ratios as well, use the nwcgr program. Since these ratios work in pairs that is how they are printed out: ./nwcgr 5 12 25:12 144:5 35:6 72:7 35:8 96:7 35:9 108:7 35:10 120:7 35:11 132:7 35:12 144:7 40:7 84:8 The above is just a small snippet of the entire output. To print out only relatively prime ratios use the rpcgr program: ./rpcgr 5 12 35:12 144:7 55:6 72:11 55:7 84:11 55:8 96:11 55:9 108:11 55:12 144:11 65:6 72:13 Again, this is just a small portion of the entire output. Once you play enough with the relatively prime clock gear ratios you will discover that there is a healthy dose of Fibonacci numbers in them: 5, 8, 13, 21, 55, 89, 144. Most are scattered here and there, some are locked into pairs: 25:12 144:5 65:12 144:13 21:13 52:7 The gcd and lcm programs are there for good measure.


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rloginunix
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Re: Mechanical Pendulum Gear Clocks, Hands
« Reply #8 on: Jul 23^{rd}, 2015, 5:26pm » 
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Literature 1) Anton, H., Bivens, I. C., Davis, S. L. (2005). Calculus, 8th edition. New York: John Wiley & Sons. 2) Baker, G. L., & Blackburn, J. A. (2005). The Pendulum, a Case Stiudy in Physics. New York: Oxford University Press. 3) Burton, D. M. (2010). Elementary Number Theory, 7th edition. New York: McGrawHill Higher Education. 4) Fichtenholz, G. M. (1962). Differential and Integral Calculus Course, 5th edition. Moscow: State Publishing House of Literature on Physics and Mathematics. 5) Goodrich, W. L. (1905). The Modern Clock. Chicago: Hazlitt & Walker. 6) Huygens, C. (1986). Geometrical Demonstrations Concerning the Motion of Pendula as Applied to Clocks. (R. J. Blackwell, Trans.). Ames: Iowa State University Press. (Original work Horologium Oscillatorium published 1673). 7) Huygens, C. (1951). Three Memoirs on Mechanics. (K. K. Baumgart, Trans.). Moscow: Publishing House of the Academy of Sciences of the USSR. (Original work Horologium Oscillatorium published 1673). 8) Landau, L. D. (1988). Mechanics. Theoretical Physics, 4th edition. Moscow: Nauka (Science). 9) Logue, C. H. (1922). American Machinist Gear Book, 3rd edition. (Trautschold, R. Ed.). New York: McGrawHill. 10) Rawlings, A. L. (1948). The Science of Clocks and Watches, 2nd edition. New York: Pitman. 11) Romanov, A. D. (1975). The Design of Time Measuring Devices. Moscow: The School of Higher Education. 12) Schwamb, P., & Merrill A. L. (1908). Elements of Mechanism, 2nd edition. New York: John Wiley & Sons.


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