

Title: Maximum Separation Post by navdeep1771 on Aug 12^{th}, 2021, 10:11pm Two bodies move in a straight line towards each other at initial velocities v1 and v2 and with constant accelerations a1 and a2 directed against the corresponding velocities at the initial instant. What must be the maximum initial separation Lmax between the bodies for which they meet during the motion? 

Title: Re: Maximum Separation Post by rmsgrey on Aug 13^{th}, 2021, 7:29am Answer: [hide]L_{max}=(v_{1} + v_{2})^{2}/(2(a_{1} + a_{2})) [/hide] Working: ::[hideb] Working in a frame where one of the bodies is stationary throughout (and ignoring relativistic corrections), the other body has initial velocity, u=v_{1}+v_{2}, and constant acceleration in the opposite direction, a=a_{1}+a_{2}. The change in separation between the two bodies, s, at a given time, t, is given by standard SUVAT formulae: s=utat^{2}/2 Since s reaches a maximum when the closing velocity, v=uat, is 0, we get: uat=0 t=u/a Substituting for t in the equation for s gives: s=u(u/a)  a(u/a)^{2}/2 =u^{2}/a  u^{2}/2a =u^{2}/2a and substituting back for u and a gives the answer above: L_{max}=(v_{1} + v_{2})^{2}/(2(a_{1} + a_{2})) [/hideb]:: edit: the subscript tags are behaving weirdly, and I can't get them to work properly edit2: fixed. Thanks towr. 

Title: Re: Maximum Separation Post by towr on Dec 29^{th}, 2021, 7:46am The tags are misbehaving because the board inserts spaces in a toolong string without any. 

Powered by YaBB 1 Gold  SP 1.4! Forum software copyright © 20002004 Yet another Bulletin Board 