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Topic: Re: Polyhedron faces (Read 948 times) |
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Aryabhatta
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Re: Polyhedron faces
« on: Mar 22nd, 2007, 12:42am » |
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Given a polyhedron, form a Graph G as follows: For each face, add a vertex to G. If faces f and g share an edge in the polyhedron, add an edge in G between corresponding vertices. The degrees of a vertex is same as the number of sides to the corresponding face. It is easy to show that any connected graph with 2 or more vertices has two vertices of same degree.
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« Last Edit: Mar 22nd, 2007, 12:48am by Aryabhatta » |
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Grimbal
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Re: Polyhedron faces
« Reply #1 on: Mar 22nd, 2007, 1:39am » |
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If there are N faces, each can have 3 to N-1 neighbours. That is N-3 values for N items. The pigeonhole principle tells there are at least 3 collisions, for instance 4 of the same type, 3 pairs, or one triplet and one pair.
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anant
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Re: Polyhedron faces
« Reply #2 on: Mar 22nd, 2007, 10:34pm » |
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It is easy to show that any connected graph with 2 or more vertices has two vertices of same degree. This again is from Pigeon Hole Principle
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shishir85
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Re: Polyhedron faces
« Reply #3 on: Mar 23rd, 2007, 9:55am » |
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on Mar 22nd, 2007, 10:34pm, anant wrote:It is easy to show that any connected graph with 2 or more vertices has two vertices of same degree. This again is from Pigeon Hole Principle |
| Can you please explain this? Thanks. Also, aryabhatta's solution seems to hold not only for convex polyhedra (as was originally asked) but for all kinds of polyhedra. Am I right?
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TenaliRaman
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Re: Polyhedron faces
« Reply #4 on: Mar 23rd, 2007, 12:32pm » |
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on Mar 23rd, 2007, 9:55am, shishir85 wrote: Can you please explain this? |
| n nodes, possible degrees of each node between 0 and n-1, the graph is connected, hence proved. -- AI
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Self discovery comes when a man measures himself against an obstacle - Antoine de Saint Exupery
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Aryabhatta
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Re: Polyhedron faces
« Reply #5 on: Mar 23rd, 2007, 12:43pm » |
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In fact, graph need not be connected. n node, 0 to n-1 degrees. Consider vertex with n-1 degree -> connected to the rest. Contradiction, hence duplicate degree.
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anant
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Re: Polyhedron faces
« Reply #6 on: Mar 27th, 2007, 11:42pm » |
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I love this forum
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