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Topic: Complex roots (Read 2158 times) |
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Grimbal
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Re: Complex roots
« Reply #25 on: Sep 27th, 2007, 12:34am » |
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on Sep 26th, 2007, 7:23pm, srn347 wrote:| As already stated, you need to have all the n's answered. x would have to equal n-1. |
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I guess you mean x-1.
Sorry to tell you that, but your understanding of mathematics is a complete mess.
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towr
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Some people are average, some are just mean.
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Re: Complex roots
« Reply #26 on: Sep 27th, 2007, 2:08am » |
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on Sep 26th, 2007, 7:23pm, srn347 wrote:| As already stated, you need to have all the n's answered. x would have to equal n-1. |
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Perhaps you misunderstand the question. What is asked for is not a single value for x that works for all n; what is asked for is an expression which given any n, provides values for x that satisfy the equation.
on Sep 26th, 2007, 9:39pm, Sameer wrote:| Note to Mods: Can you please delete posts that are irrelevant to this thread? You get my drift!! |
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If this final attempt at explanation fails, I'll be glad to. So that should be in under a day.
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Wikipedia, Google, Mathworld, Integer sequence DB
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srn437
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Re: Complex roots
« Reply #27 on: Sep 27th, 2007, 4:46pm » |
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Oh individual values. Obviously the evens are already solved. Some exponents may have multiple solutions.
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pex
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Re: Complex roots
« Reply #28 on: Sep 28th, 2007, 12:10am » |
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on Sep 27th, 2007, 4:46pm, srn347 wrote:| Oh individual values. Obviously the evens are already solved. Some exponents may have multiple solutions. |
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srn347 - A complete solution was outlined in the first three replies to this thread. Indeed, there are multiple solutions: n-1 for every n.
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| « Last Edit: Sep 28th, 2007, 12:11am by pex » |
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