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Topic: Convergent or Divergent? (Read 2191 times) |
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ThudnBlunder
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Convergent or Divergent?
« on: Nov 26th, 2008, 8:31am » |
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 (nlogn.loglogn)-1
n=3
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| « Last Edit: Nov 26th, 2008, 1:15pm by ThudnBlunder » |
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Obob
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Re: Convergent or Divergent?
« Reply #1 on: Dec 1st, 2008, 9:29pm » |
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Integral test.
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ThudnBlunder
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Re: Convergent or Divergent?
« Reply #2 on: Dec 4th, 2008, 3:49pm » |
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on Dec 1st, 2008, 9:29pm, Obob wrote:
Ah yes, I hadn't realized that the integral of the given function is logloglogx. 
Perhaps I should have asked how many terms are required for the sum to exceed 10.
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ThudnBlunder
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Re: Convergent or Divergent?
« Reply #3 on: Dec 15th, 2008, 7:21pm » |
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on Dec 4th, 2008, 3:49pm, ThudanBlunder wrote:
Perhaps I should have asked how many terms are required for the sum to exceed 10.
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Let N = Number of terms required for function to exceed 10
F(n): 1/loglog(n) for n > 2
N: 1
F(n): 1/log(n) for n > 1
N: 20
F(n): 1/ n for n > 0
N: 33
F(n): 1/n for n > 0
N: 12367
F(n): 1/nlog(n) for n > 1
N: 104300
F(n): 1/[nlog(n)*loglog(n)] for n > 2
N: googolplex
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