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ThudnBlunder
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 Convergent or Divergent?   « on: Nov 26th, 2008, 8:31am » Quote Modify

(nlogn.loglogn)-1
n=3
 « Last Edit: Nov 26th, 2008, 1:15pm by ThudnBlunder » IP Logged

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Obob
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 Re: Convergent or Divergent?   « Reply #1 on: Dec 1st, 2008, 9:29pm » Quote Modify

Integral test.
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ThudnBlunder
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 Re: Convergent or Divergent?   « Reply #2 on: Dec 4th, 2008, 3:49pm » Quote Modify

on Dec 1st, 2008, 9:29pm, Obob wrote:
 Integral test.

Ah yes, I hadn't realized that the integral of the given function is logloglogx.

Perhaps I should have asked how many terms are required for the sum to exceed 10.
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ThudnBlunder
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 Re: Convergent or Divergent?   « Reply #3 on: Dec 15th, 2008, 7:21pm » Quote Modify

on Dec 4th, 2008, 3:49pm, ThudanBlunder wrote:
 Perhaps I should have asked how many terms are required for the sum to exceed 10.

Let N = Number of terms required for function to exceed 10

F(n): 1/loglog(n) for n > 2
N: 1

F(n): 1/log(n) for n > 1
N: 20

F(n): 1/n for n > 0
N: 33

F(n): 1/n for n > 0
N: 12367

F(n): 1/nlog(n) for n > 1
N: 104300

F(n): 1/[nlog(n)*loglog(n)] for n > 2
N: googolplex

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