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   Euler phi is DFT of GCD
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   Author  Topic: Euler phi is DFT of GCD  (Read 2292 times)
Eigenray
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Euler phi is DFT of GCD  
« on: Jan 27th, 2009, 11:53am »
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I saw this cute result on the Wikipedia:
 
(n) = k=1n  gcd(k,n) cos(2k/n)
« Last Edit: Jan 30th, 2009, 12:05pm by Eigenray » IP Logged
towr
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Re: Euler phi is DFT of GCD  
« Reply #1 on: Jan 27th, 2009, 12:19pm »
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"gcd" is missing in front of (k,n)
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ThudnBlunder
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Re: Euler phi is DFT of GCD  
« Reply #2 on: Jan 27th, 2009, 12:56pm »
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on Jan 27th, 2009, 11:53am, Eigenray wrote:
I saw this cute result on the Wikipedia:
 
(n) = k=1n  (k,n) cos(2k/n)

I saw this cute result elsewhere:
 
If (n)/n = 5/3 then 5n is an odd perfect number
where (n) is the sum of the divisors of the positive integer n, including 1 and n.  
 
The idea crossed my mind to post it as a problem: Find an n such that (n)/n = 5/3
And then, after you had duly found one, to claim my 15 minutes of fame and fortune before you wised up. LOL
 
« Last Edit: Jan 30th, 2009, 12:34pm by ThudnBlunder » IP Logged

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balakrishnan
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Re: Euler phi is DFT of GCD  
« Reply #3 on: Jan 30th, 2009, 10:36am »
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Here  is an interesting article.
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Eigenray
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Re: Euler phi is DFT of GCD  
« Reply #4 on: Jan 30th, 2009, 12:14pm »
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on Jan 27th, 2009, 12:19pm, towr wrote:
"gcd" is missing in front of (k,n)

I think it's clear from the context but if you insist...
 
on Jan 30th, 2009, 10:36am, balakrishnan wrote:
Here  is an interesting article.

Unfortunately their forms use post requests so a direct link won't work.  Which one are you referring to?
 
Anyway, the result is not hard to prove; I only put it in this section because it seemed too abstract for a riddle.
 
Hint: What is the sum of all primitive m-th roots unity?
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balakrishnan
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Re: Euler phi is DFT of GCD  
« Reply #5 on: Jan 30th, 2009, 12:42pm »
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Oh, sorry: I was referring to ."The Fourier Transform of Functions of the Greatest Common Divisor "  by Wolfgang Schramm
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