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   A challenge
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   Author  Topic: A challenge  (Read 1562 times)
Icarus
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Re: A challenge  
« Reply #25 on: Oct 28th, 2003, 5:32pm »
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on Oct 28th, 2003, 12:49am, towr wrote:
Yes I agree, so here's the proper order. While BNC first allowed e, he reconsidered, since it's a constant (and thus another number)

 
Sorry - somehow I missed that in my reading of the thread! Embarassed (Sigh, more remarks are coming about people who post to threads without reading them... Undecided) )
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"Pi goes on and on and on ...
And e is just as cursed.
I wonder: Which is larger
When their digits are reversed? " - Anonymous
towr
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Re: A challenge  
« Reply #26 on: Oct 29th, 2003, 12:11am »
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on Oct 28th, 2003, 5:32pm, Icarus wrote:
Sorry - somehow I missed that in my reading of the thread! Embarassed
Don't worry about it, it happens to the best of us (apparantly Wink)
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SWF
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Re: A challenge  
« Reply #27 on: Nov 5th, 2003, 5:58pm »
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I would like to add a $ to the formula I gave on Oct. 27.  I just found out that n$ means "superfactorial":
 
n$= (n!)^(n!)^(n!)^...^(n!)
 
where the number of ^'s is n!-1.
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BNC
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Re: A challenge  
« Reply #28 on: Nov 10th, 2003, 2:36pm »
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It seems we're getting a real mammoth of a number (thanks, SWF).
 
I think I have an improvement to the "core" number. I figure we may use the "E" notation (e.g., 500 = 5E2) to get:
[(.1%)‰]-2E3, which should be a rather largee number (especially after the multidute factorials...)
« Last Edit: Nov 10th, 2003, 2:37pm by BNC » IP Logged

How about supercalifragilisticexpialidociouspuzzler [Towr, 2007]
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