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Topic: A challenge (Read 1562 times) |
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Icarus
wu::riddles Moderator Uberpuzzler
Boldly going where even angels fear to tread.
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Posts: 4863
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Re: A challenge
« Reply #25 on: Oct 28th, 2003, 5:32pm » |
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on Oct 28th, 2003, 12:49am, towr wrote:Yes I agree, so here's the proper order. While BNC first allowed e, he reconsidered, since it's a constant (and thus another number) |
| Sorry - somehow I missed that in my reading of the thread! (Sigh, more remarks are coming about people who post to threads without reading them... ) )
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"Pi goes on and on and on ... And e is just as cursed. I wonder: Which is larger When their digits are reversed? " - Anonymous
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towr
wu::riddles Moderator Uberpuzzler
Some people are average, some are just mean.
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Posts: 13730
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Re: A challenge
« Reply #26 on: Oct 29th, 2003, 12:11am » |
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on Oct 28th, 2003, 5:32pm, Icarus wrote:Sorry - somehow I missed that in my reading of the thread! |
| Don't worry about it, it happens to the best of us (apparantly )
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Wikipedia, Google, Mathworld, Integer sequence DB
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SWF
Uberpuzzler
Posts: 879
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Re: A challenge
« Reply #27 on: Nov 5th, 2003, 5:58pm » |
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I would like to add a $ to the formula I gave on Oct. 27. I just found out that n$ means "superfactorial": n$= (n!)^(n!)^(n!)^...^(n!) where the number of ^'s is n!-1.
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BNC
Uberpuzzler
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Re: A challenge
« Reply #28 on: Nov 10th, 2003, 2:36pm » |
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It seems we're getting a real mammoth of a number (thanks, SWF). I think I have an improvement to the "core" number. I figure we may use the "E" notation (e.g., 500 = 5E2) to get: [(.1%)‰]-2E3, which should be a rather largee number (especially after the multidute factorials...)
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« Last Edit: Nov 10th, 2003, 2:37pm by BNC » |
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How about supercalifragilisticexpialidociouspuzzler [Towr, 2007]
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