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   MasterMind II soln
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   Author  Topic: MasterMind II soln  (Read 1517 times)
zeb
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MasterMind II soln  
« on: Jul 30th, 2002, 1:08pm »
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G: Green  
R: Red  
Y: Yellow  
B: Brown  
L: Light Blue  
D: Dark Blue  
 
black peg: .  
White peg: o  
 
reversing the order, my apologies:  
1) LDRG o  
2) LYGB .o
3) GGYL ..
4) YGLB .o
5) ----? ....
 
1) tells us one of these is part of the solution but no others.  
L  has no obvious conflicts
D breaks at 3), since if LDG are all not part of the solution, then 3) can’ t have two black pegs.
R likewise breaks at 3) for the same reason
G has no obvious conflicts.
 
Assume G is the o from 1), LDR are all out.
  2)  Either Y, G or B is the .
    If Y, then G isn’t in either of the last 2 so GY-- would be true. But that cannot be since it would give at least one white peg for 3) instead of the .. we see.  
    If G, then --G- is all we know and Y or B is misplaced.  
 Y can’t be the misplaced one since 3) would then show a white peg. For there to be only black pegs would put Y and G on the same spot, so Y isn’t the one.  
 If B is misplaced, then 3) would not work since YL are not true for this tree, leaving GG as true and sitting on the only spots where B could be true. B ain't it.
    So G is not the one.
 
Which leaves L. But, to be sure (or if you start with L instead of G)…
 
Assuming L, 1) tells us DRG are all out.
So 3) then tells us --YL is part of the solution.  
B cannot be part of the solution. If it were, then B-YL or –BYL would make 4) show 3 pegs, and 2) would show 3 pegs, which they don’t.  
So that leaves only Y and L for the remaining spots.  
L can’t be in the first spot because of 1). So, Y must be there.  
2) tells us Y is in the 2nd spot too, since L is still the white peg from 1).
 
YYYL.
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Snack
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Re: MasterMind II soln  
« Reply #1 on: Aug 21st, 2002, 3:23pm »
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I got exactly the same thing.
 
I started by going through all the possibilities created by 3 and then working from there. Smiley
 
YYYL
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allie
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Re: MasterMind II soln  
« Reply #2 on: Nov 14th, 2002, 9:01am »
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*Sigh*  Nope, I can't see it.  If indeed 3 tells us that --YL must be true, then 2 would have 2 "o"'s (since the colors are right but the position isn't).  Instead it has ".o".  So if you accept that YL are in the final, it's either "L-Y-" (which can't be because of 3) or "-Y-L" (which can't be beacuse of 3).  So "YL" can't be part of the final solution because 3 says they would have to be in 3rd and 4th position, and 2 does not have 2 color only marks to support that.  *Sigh again*  Did I explain that well?  Can anyone explain this one to me?
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