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Topic: Casino Bus (Read 3046 times) |
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denis
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Re: Casino Bus
« Reply #50 on: Feb 5th, 2007, 7:50am » |
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So WTF, you see what is happenning here? You're red hot now. I stared at the schedule for almost a day before everything clicked.
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| « Last Edit: Feb 5th, 2007, 7:59am by denis » |
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towr
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Re: Casino Bus
« Reply #51 on: Feb 5th, 2007, 7:54am » |
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on Feb 5th, 2007, 7:07am, denis wrote:| Not sure what you mean here. |
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The same people going in and out multiple times.
Around here busses have doors at multiple points, so you could leave through one, get in through the other, leave the bus again, etc.
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denis
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Re: Casino Bus
« Reply #52 on: Feb 5th, 2007, 7:57am » |
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on Feb 5th, 2007, 7:54am, towr wrote:
The same people going in and out multiple times.
Around here busses have doors at multiple points, so you could leave through one, get in through the other, leave the bus again, etc.
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OK I see. No..This does not involve revolving doors. Only one door is at the front.
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Whiskey Tango Foxtrot
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Re: Casino Bus
« Reply #53 on: Feb 5th, 2007, 8:12am » |
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Oh! I get it! If you want me to post it I will but I assure you I have the answer.
That's really odd, isn't it?
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| « Last Edit: Feb 5th, 2007, 8:13am by Whiskey Tango Foxtrot » |
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denis
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Re: Casino Bus
« Reply #54 on: Feb 5th, 2007, 8:19am » |
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Go ahead and post it..You deserve the kudos.. (you may also have an alternate solution that I didn't think of).
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| « Last Edit: Feb 5th, 2007, 8:22am by denis » |
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Whiskey Tango Foxtrot
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Re: Casino Bus
« Reply #55 on: Feb 5th, 2007, 8:47am » |
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Well, I'll take a stab at two different answers, then. They passed through the same station twice, once on their way West, once as they went to the East. As a possible alternate, the same passengers could have probably transferred to a different bus and caught the original bus at a different station. I'm pretty sure the first one is the intended.
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denis
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Re: Casino Bus
« Reply #56 on: Feb 5th, 2007, 9:01am » |
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on Feb 5th, 2007, 8:47am, Whiskey Tango Foxtrot wrote:| Well, I'll take a stab at two different answers, then. They passed through the same station twice, once on their way West, once as they went to the East. As a possible alternate, the same passengers could have probably transferred to a different bus and caught the original bus at a different station. I'm pretty sure the first one is the intended. |
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I like your second answer better (its the intended one) but with a bit of simplification.... Is there any reason why they need to get back on the original bus? Where in the riddle does it say that the same bus arrived at Atlantic City as the bus that left Newark? Its an assumption we all make which makes the solution more difficult to get. In fact, I don't believe that ANY bus leaving Newark actually arrive at Atlantic City according to the schedules. All routes that I checked have a compulsary transfer. The simple compulsary transfer scenario from the original bus onto a second bus where there are already passengers would be simpler and works just as well. (note: Some of the routes only have one transfer and is the intended solution).
BTW you may wonder why I didn't accept your transfer suggestion a few posts back. It seemed to me you were transfering passengers from other busses to the original one. It was important to understand the transfer went the other way
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| « Last Edit: Feb 5th, 2007, 9:30am by denis » |
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Grimbal
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Re: Casino Bus
« Reply #57 on: Feb 5th, 2007, 9:36am » |
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on Feb 5th, 2007, 2:39am, Grimbal wrote:| "when the bus arrived in Atlantic City" happened before the 15 passengers embarked in Newark. Maybe it is not even the same "Atlantic City" as the "Atlantic City, NJ", the intended destination of the 15 people from Newark. |
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on Feb 5th, 2007, 7:07am, denis wrote:| If there is another Atlantic City on Greyhound's published route from Newark to Atlantic City, NJ I would be very surprised but I would nonetheless accept it as an alternate solution. |
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I was thinking of the following sequence of events:
- 15 passengers get down from the bus at Atlantic City
- The bus arrives empty at Newark and 15 passengers embark
- A stop somewhere, 10 passenger leave, 5 get back,
- whatever happens to the bus then is not part of the story
This seems to match your account of events.
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| « Last Edit: Feb 5th, 2007, 9:40am by Grimbal » |
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Whiskey Tango Foxtrot
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Re: Casino Bus
« Reply #58 on: Feb 5th, 2007, 9:42am » |
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on Feb 5th, 2007, 9:01am, denis wrote:| Is there any reason why they need to get back on the original bus? Where in the riddle does it say that the same bus arrived at Atlantic City as the bus that left Newark? Its an assumption we all make which makes the solution more difficult to get. |
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For me it was the fact that other than the first line, which introduces an empty bus, in every other reference to a bus you use "the bus" and not "a bus." I'm not saying you were wrong for doing this, but that is why I made the assumption that there was only one bus.
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denis
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Re: Casino Bus
« Reply #59 on: Feb 5th, 2007, 10:08am » |
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on Feb 5th, 2007, 9:36am, Grimbal wrote:
I was thinking of the following sequence of events:
- 15 passengers get down from the bus at Atlantic City
- The bus arrives empty at Newark and 15 passengers embark
- A stop somewhere, 10 passenger leave, 5 get back,
- whatever happens to the bus then is not part of the story
This seems to match your account of events. |
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Yes your description does look like an alternate. You're basically opening up the timelime to have the bus do things in a sequence that would make sense. I'm trying to decide wether to accept it given the fact that the bus arriving in Atlantic City is different from the bus leaving Newark according to Greyhound schedule. To be fair, you are not bound by their schedule but only the clues given by the riddle so I will accept it as alternate....
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| « Last Edit: Feb 5th, 2007, 10:13am by denis » |
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denis
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Re: Casino Bus
« Reply #60 on: Feb 5th, 2007, 10:17am » |
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on Feb 5th, 2007, 9:42am, Whiskey Tango Foxtrot wrote:
For me it was the fact that other than the first line, which introduces an empty bus, in every other reference to a bus you use "the bus" and not "a bus." I'm not saying you were wrong for doing this, but that is why I made the assumption that there was only one bus. |
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In my way of thinking when your on a bus route, you simply refer to the bus you're on as "the" bus and not "a" bus. Yes I suppose now I could of used "their bus" on the last line and this would have made it less deceptive. I hope you all enjoyed the riddle nothwitstanding this small hiccup.
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| « Last Edit: Feb 5th, 2007, 10:35am by denis » |
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towr
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Re: Casino Bus
« Reply #61 on: Feb 5th, 2007, 10:32am » |
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For a transfer to happen, I would assume they have to disembark and reembark, and it's clearly stated no such thing occurs.
It'd work for trains though, as you can just join two trains together.
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denis
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Re: Casino Bus
« Reply #62 on: Feb 5th, 2007, 10:39am » |
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The riddle says "No other passengers embarked on the bus at this or other stops along the route since departure from Newark, NJ." The first bus is the one that had departed from Newark, so we are referring to the first bus here. Since the second bus did not have a departure from Newark, embarkation to the second bus is allowed. Also, disembarkation from the first bus is allowed in the riddle.
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| « Last Edit: Feb 5th, 2007, 10:51am by denis » |
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jollytall
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Re: Casino Bus
« Reply #63 on: Feb 5th, 2007, 11:33am » |
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I thought of the physical coupling of a second coach (trailer) to the original bus along the route (like a train). That would solve the physical bus solution, but it was excluded by the comment "one door only". So I did not even post it.
But even with the official solution I have a problem.
I accept the fact that we are talking of a "virtual" bus (THE bus), that is practically a bus-line. But then I have the question. Is the bus(line) that arrives to AC is the same as the one departs from Newark.
If yes, then the passengers arriving on the other physical bus, also come on a different bus(line), so they DO embark this bus(line) even without getting down from their physical bus.
If not (either the merged part inherites the code of the other branch, or it gets a totally new number), then the first bus(line) actually never arrives to AC, so they cannot get off it at all there, i.e. the riddle is incorrect.
A third solution is that it becomes a code-sharing leg of the journey, sort of both virtual buses arriving to AC. But since we are talking of bus(lines) not physical buses, actually the two group of passengers get down from two bus(line)s even if they travelled on one physical bus. So from "OUR" bus only 10 people get down.
The only case that I can imagine and accept if the two bus(line)s have exactly the same number/code. Well, if it is so, then it can be very confusing over there.
I still like my "catching up" version most, even in the form of the bus making a loop and stopping at the same stop again picking up the same passangers, not others. (Yes it does not work with 25.)
Yes, I know: only the grape is sour.
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denis
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Re: Casino Bus
« Reply #64 on: Feb 5th, 2007, 12:11pm » |
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on Feb 5th, 2007, 11:33am, jollytall wrote:I thought of the physical coupling of a second coach (trailer) to the original bus along the route (like a train). That would solve the physical bus solution, but it was excluded by the comment "one door only". So I did not even post it.
But even with the official solution I have a problem.
I accept the fact that we are talking of a "virtual" bus (THE bus), that is practically a bus-line. But then I have the question. Is the bus(line) that arrives to AC is the same as the one departs from Newark.
If yes, then the passengers arriving on the other physical bus, also come on a different bus(line), so they DO embark this bus(line) even without getting down from their physical bus.
If not (either the merged part inherites the code of the other branch, or it gets a totally new number), then the first bus(line) actually never arrives to AC, so they cannot get off it at all there, i.e. the riddle is incorrect.
A third solution is that it becomes a code-sharing leg of the journey, sort of both virtual buses arriving to AC. But since we are talking of bus(lines) not physical buses, actually the two group of passengers get down from two bus(line)s even if they travelled on one physical bus. So from "OUR" bus only 10 people get down.
The only case that I can imagine and accept if the two bus(line)s have exactly the same number/code. Well, if it is so, then it can be very confusing over there.
I still like my "catching up" version most, even in the form of the bus making a loop and stopping at the same stop again picking up the same passangers, not others. (Yes it does not work with 25.)
Yes, I know: only the grape is sour. |
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Jollytall,
You are correct in that in a virtual bus line the first bus line (code) does not get to the destination. A different line number is served by the second bus.
The Newark to Atlantic City routes is served by two different bus routes (or codes as you put it).
But note on the bus ticket, there is a departure city with a bus code, a transfer city with a new bus code and a destination city. Since you can print a bus ticket with Newark as departure, and Atlantic City as destination, you can certainly get off Atlantic City on this virtual bus from my point of view.
However, I do admit that my initial intention was to just talk about physical busses and I should have changed the last line to reflect that ("their bus" instead of "the" bus) to emphasise physical busses rather than virtual bus.
I appreciate your comments on how I could have handled the riddle differently as I am still in the learning process.
And your solution is not all that bad to tell you the truth. I guess sometimes the guy who writes the riddle will accept some solution over others based on certain criteria. My criteria was what really happens on the Newark to AC bus route based on Greyhound's published shedules. It was a "real world" riddle. I trew in 15 at destination and at departure in order to put riddlers on a false trail (and you bit). So I considered answers that solely concentrated on the equal numbers at destination and departure as being off the trail from before the start of the riddle (perhaps unfairly).
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| « Last Edit: Feb 5th, 2007, 1:30pm by denis » |
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C.S.I.
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Re: Casino Bus
« Reply #65 on: Feb 5th, 2007, 1:17pm » |
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denis, on behalf of jollytall, please don't get his name wrong.. 
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denis
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Re: Casino Bus
« Reply #66 on: Feb 5th, 2007, 1:31pm » |
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My bad.....C.S.I.
Thanks for pointing it out.
Error corrected.
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| « Last Edit: Feb 5th, 2007, 1:32pm by denis » |
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jollytall
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Re: Casino Bus
« Reply #67 on: Feb 5th, 2007, 11:14pm » |
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Oh, I missed that. What was it?
Jollytail? I like that. I do my best to keep it like that (my tail to be happy) 
Something else? Let me know.
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CowsRUs
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Re: Casino Bus
« Reply #68 on: Feb 6th, 2007, 6:53pm » |
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i thought differently the intended one puzzled me but Of the ten passengers that got off, only 5 of them got on... that doesnt regard new passengers, but i guess i was wrong or misunderstood a few posts
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Icarus
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Re: Casino Bus
« Reply #69 on: Feb 6th, 2007, 6:55pm » |
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on Feb 5th, 2007, 10:17am, denis wrote:In my way of thinking when your on a bus route, you simply refer to the bus you're on as "the" bus and not "a" bus. Yes I suppose now I could of used "their bus" on the last line and this would have made it less deceptive. I hope you all enjoyed the riddle nothwitstanding this small hiccup.
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In my opinion, you should of gone with "their bus" for the final line. By saying "the bus", you were not just being a little deceptive, but downright lying (not intentionally, I know). But hindsight is 20/20. 
Thanks for the riddle.
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