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Topic: An inequality (Read 1070 times) |
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acarchau
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An inequality
« on: Dec 14th, 2008, 9:48pm » |
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Prove/disprove, for x>=0 (1+x)^(1+x) >= 1+x+x^2
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towr
wu::riddles Moderator Uberpuzzler
Some people are average, some are just mean.
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Re: An inequality
« Reply #1 on: Dec 15th, 2008, 1:38am » |
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take f(x) = (1+x)^(1+x) g(x) = 1+x+x^2 then f(0)=g(0) f'(0)=g'(0) f''(x) >= g''(x) for x>=0 so (since they are continuous) f(x) >= g(x) for x>=0
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Wikipedia, Google, Mathworld, Integer sequence DB
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ThudnBlunder
Uberpuzzler
The dewdrop slides into the shining Sea
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Re: An inequality
« Reply #2 on: Dec 15th, 2008, 3:30am » |
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Binomial Theorem.
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THE MEEK SHALL INHERIT THE EARTH.....................................................................er, if that's all right with the rest of you.
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