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   Author  Topic: even-odd  (Read 412 times)
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even-odd  
« on: Apr 7th, 2003, 12:22pm »		 Quote Quote Modify Modify
In the following multiplication, each even figure is replaced by an "E", and each odd by an "O". What is the result?
 
 
Code:

 
   OEO
 X
   EOE
   ---
  EEEE
  OOO
OEEE
--------
OOOOOE
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How about supercalifragilisticexpialidociouspuzzler [Towr, 2007]
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Re: even-odd  
« Reply #1 on: Apr 7th, 2003, 12:57pm »		 Quote Quote Modify Modify Remove Remove
Answer:
labeling the digits for easy explanations:
abc
x
def
___
 
AF>20: AE<10: E is not 1. Therefore A=3  and E = 3
BE<10: B=0 or 2
10<CE<20: C=5
AD results in OddEven, so B=0 and D=4
20<AF<30: F=8
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