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Topic: Dan's Farm (Read 3573 times) |
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ThudnBlunder
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Although The Farm, a rectangular piece of land, has been in Dan's family for a good number of years, he is thinking of selling it, as Britain has just declared war on Hitler.
ACROSS
1. Area in square yards of The Farm.
5. Age of Molly, Dan's aunt.
6. Number of yards difference between length and width of The Farm.
7. Area of The Farm in quarter-acres times 8 Down.
8. The year Dan's family bought The Farm.
10. Dan's age.
11. Year of Maria's birth.
14. Perimeter in yards of The Farm.
15. Dan's mph walking speed cubed.
16. 15 Across take away 9 Down.
DOWN
1. Five times the value of The Farm in pounds sterling per acre.
2. Age of Dan's mother-in-law squared.
3. Age of Maria, Dan's daughter.
4. Value in pounds sterling of The Farm.
6. Age of Tom, Dan's son, who will be twice Maria's age in 1945.
7. Square of the width of The Farm.
8. The number of minutes it takes Dan to walk 4/3 times round The Farm.
9. 10 Down divided by 10 Across.
10. See 9 Down.
12. One more than the sum of the digits of 10 Down.
13. The number of years The Farm has been in Dan's family.
(1 mile = 1760 yards; 1 acre = 4840 square yards.)
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| « Last Edit: Sep 20th, 2007, 4:40am by ThudnBlunder » |
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THE MEEK SHALL INHERIT THE EARTH.....................................................................er, if that's all right with the rest of you.
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Barukh
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Re: Dan's Farm
« Reply #1 on: Sep 20th, 2007, 4:24am » |
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What happened to the picture? I can't see it!
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ThudnBlunder
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Re: Dan's Farm
« Reply #2 on: Sep 20th, 2007, 4:42am » |
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on Sep 20th, 2007, 4:24am, Barukh wrote:| What happened to the picture? I can't see it! |
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You were getting too close! 
I want to put the picture in the middle using [img][/img]. The gif is on the server, so why doesn't it come up when referenced?
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THE MEEK SHALL INHERIT THE EARTH.....................................................................er, if that's all right with the rest of you.
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towr
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Re: Dan's Farm
« Reply #3 on: Sep 20th, 2007, 5:01am » |
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on Sep 20th, 2007, 4:42am, ThudanBlunder wrote:
You were getting too close!
I want to put the picture in the middle using [img][/img]. The gif is on the server, so why doesn't it come up when referenced?
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It is only on the server while it's attached. If you remove it as attachment, it is also removed from the server. If you want it shown in the post, rather than under it, you might try attaching it as txt and linking that as an image.
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Barukh
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on Sep 20th, 2007, 4:42am, ThudanBlunder wrote:
You were getting too close! |
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No, I am stupid.
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ThudnBlunder
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Re: Dan's Farm
« Reply #5 on: Sep 20th, 2007, 7:09am » |
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on Sep 20th, 2007, 5:27am, Barukh wrote:
What happened to your PMed allleged contradictions?
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Barukh
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Re: Dan's Farm
« Reply #6 on: Sep 20th, 2007, 7:23am » |
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on Sep 20th, 2007, 7:09am, ThudanBlunder wrote:
What happened to your PMed allleged contradictions? |
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I haven't thought a farm could be in possession of a single family for so long...
I wonder: how much such a farm costs nowadays in England?
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ThudnBlunder
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Re: Dan's Farm
« Reply #7 on: Sep 20th, 2007, 7:43am » |
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on Sep 20th, 2007, 7:23am, Barukh wrote:| I wonder: how much such a farm costs nowadays in England? |
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Between 1 and 2 million pounds (US$2-4m), I am told.
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| « Last Edit: Sep 21st, 2007, 12:06pm by ThudnBlunder » |
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ThudnBlunder
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Re: Dan's Farm
« Reply #8 on: Sep 21st, 2007, 12:08pm » |
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Well, is nobody going to post a solution for this nice puzzle?
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Sameer
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Re: Dan's Farm
« Reply #9 on: Sep 21st, 2007, 2:05pm » |
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on Sep 21st, 2007, 12:08pm, ThudanBlunder wrote:| Well, is nobody going to post a solution for this nice puzzle? |
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I will work over weekend on this!!!
Edit: I tried a little and saw myself going round and round!! Any hints would be appreciated!!
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| « Last Edit: Sep 21st, 2007, 7:52pm by Sameer » |
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"Obvious" is the most dangerous word in mathematics.
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Proof is an idol before which the mathematician tortures himself.
Sir Arthur Eddington, quoted in Bridges to Infinity
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FiBsTeR
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Re: Dan's Farm
« Reply #10 on: Sep 21st, 2007, 6:29pm » |
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on Sep 19th, 2007, 2:33pm, ThudanBlunder wrote:
9. 10 Down divided by 10 Across.
10. See 9 Down.
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Does "See 9 Down" mean that 10 Down is equal to 9 Down? In that case:
(10 Down) = (10 Down) / (10 Across)
(10 Across) = 1
Dan's Age = 1
 I guess I'm misinterpreting...
EDIT: Ah, maybe you mean that 10 Down can be ascertained only by getting 9 Down first...
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| « Last Edit: Sep 21st, 2007, 6:34pm by FiBsTeR » |
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SWF
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Re: Dan's Farm
« Reply #11 on: Sep 21st, 2007, 8:00pm » |
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Here is a hint: I started with first digit of 11 across must be 1, since this is prior to 1945 (and assumed no leading zeros), then was able to figure out cube of walking speed.
I didn't notice the Hitler clue until only 5 more cells left to fill and can't help but wonder if using that sooner would have made it easier.
38720X5
4X91X44
0X2X384
X1110XX
72X1918
9XXX792
27X16X9
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towr
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Re: Dan's Farm
« Reply #12 on: Sep 22nd, 2007, 3:09am » |
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on Sep 21st, 2007, 12:08pm, ThudanBlunder wrote:| Well, is nobody going to post a solution for this nice puzzle? |
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Didn't Barukh post one?
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ThudnBlunder
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Re: Dan's Farm
« Reply #13 on: Sep 22nd, 2007, 12:13pm » |
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on Sep 22nd, 2007, 3:09am, towr wrote:
But I'm a bit weird, I differentiate between answers and solutions.
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THE MEEK SHALL INHERIT THE EARTH.....................................................................er, if that's all right with the rest of you.
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ThudnBlunder
wu::riddles Moderator
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The dewdrop slides into the shining Sea
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Re: Dan's Farm
« Reply #14 on: Sep 22nd, 2007, 12:17pm » |
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on Sep 21st, 2007, 6:29pm, FiBsTeR wrote:
EDIT: Ah, maybe you mean that 10 Down can be ascertained only by getting 9 Down first... |
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It simply means 10 Down depends on 9 Down.
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THE MEEK SHALL INHERIT THE EARTH.....................................................................er, if that's all right with the rest of you.
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Barukh
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Re: Dan's Farm
« Reply #15 on: Oct 3rd, 2007, 2:21am » |
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on Sep 22nd, 2007, 12:13pm, ThudanBlunder wrote:| But I'm a bit weird, I differentiate between answers and solutions. |
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Here's one:
The solution is somewhat simplified by the fact that the problem is put in a certain historical context. For instance, this almost immediately implies 9D = 11.
Proceed with 15A, which can be 27 or 64. If 15A = 64, we must have 8D = 16, but then 14A = 8D * 88 > 1000, which is impossible. Therefore, 15A = 27, 8D = 12, 14A = 8D * 66 = 792. Applying the conditions for 12D, 10A, 10D, I found the only possible case 10A = 72, 10D = 792, 12D = 19. Also, 11A = 191?, 7D = ??976, which has a unique solution 30976 as a perfect square. Thus, the dimensions of the farm are determined (220 x 176), and 1A = 38720, 6A = 44.
Now, from the condition 6D, 3D is determined uniquely to be 21. The rest is straightforward.
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