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Topic: Another Sine Product (Read 553 times) |
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CSter
Newbie
Posts: 2
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Another Sine Product
« on: May 18th, 2004, 4:24pm » |
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Here is a sine product formula that I've run across: n = 2n-1[prod]k=1n-1sin(k[pi]/n) Anyone familiar with it? Can you prove it?
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Icarus
wu::riddles Moderator Uberpuzzler
Boldly going where even angels fear to tread.
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Posts: 4863
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Re: Another Sine Product
« Reply #1 on: May 18th, 2004, 10:18pm » |
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See my post in the other thread.
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"Pi goes on and on and on ... And e is just as cursed. I wonder: Which is larger When their digits are reversed? " - Anonymous
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