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   Author  Topic: Another Sine Product  (Read 553 times)
CSter
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Another Sine Product  
« on: May 18th, 2004, 4:24pm »
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Here is a sine product formula that I've run across:
 
n = 2n-1[prod]k=1n-1sin(k[pi]/n)
 
Anyone familiar with it? Can you prove it?
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Icarus
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Re: Another Sine Product  
« Reply #1 on: May 18th, 2004, 10:18pm »
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See my post in the other thread.
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"Pi goes on and on and on ...
And e is just as cursed.
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